We need the dissociation constant of benzoic acid which is 6.3x10^'5. Then using the dissociation formula, ka = x2 / (Mo - x) where Mo is the initial concentration. x is determined then. percent ionization is computed as (x/Mo)* 100%. This is then the final answer.
6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g 119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.
Answer::Molarity = 0.08 MExplanation:Given data:Mass of sodium carbonate = 10.6 gVolume of water = 1.25 LMolarity of solution = ?Solution:First of ... 10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters of solution.
