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rewona [7]
3 years ago
13

Mark all of the objects that can be found in our Solar System

Chemistry
1 answer:
STALIN [3.7K]3 years ago
4 0

Answer:

major planets ,asteroids, nebula and dust

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What mass of mgo is produced from 2.00 moles of mg ? Mg +02 mgo
Vanyuwa [196]
Chemical Reactions and Moles of Reactants and Products
That is, it requires 2 moles of magnesium and 1 mole of oxygen to produce 2 moles of magnesium oxide. If only 1 mole of magnesium was present, it would require 1 ÷ 2 = ½ mole of oxygen gas to produce 2 ÷ 2 = 1 mole magnesium oxide.
3 0
3 years ago
Find the molality of the solution if 42 grams of lithium chloride (LiCl) are dissolved in 3.6 kg of water.
omeli [17]
The molality is calculated using the following rule:
molality = number of moles of solute / kg of solvent

From the periodic table:
molar mass of lithium = 6.941 gm
molar mass of chlorine = 35.453 gm

molar mass of LiCl = 6.941 + 35.453 = 42.394 gm
number of moles found in 42 gm = mass / molar mass = 42 / 42.394 = 0.99

molality = 0.99 / 3.6 = 0.275 m
3 0
3 years ago
Show all work and units cancellation. 1000mL = 1 L, 1000 g = 1kg
pantera1 [17]

Answer:

75300g

Explanation:

2. 75.3 kg to grams

  • 75.3kg×1000g/1kg
5 0
3 years ago
A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

3 0
3 years ago
Which is a potential benefit of genetic engineering in agriculture? higher levels of toxins disruption of other genes increased
MrMuchimi

Answer:

increase in the size of fruits and vegetables

8 0
3 years ago
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