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2 years ago

A 0.250 L solution is made with 1.60 g of glucose, in water at 25.00∘C. What is the osmotic pressure of the solution?

1 answer:

5 0

The osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

<h3>How to calculate osmotic pressure?</h3>

The osmotic pressure of the solution can be calculated using the following expression:

PV = nRT

where;

P = pressure
V = volume
n = no of moles
T = temperature
R = gas law constant

no of moles of glucose = 1.60g ÷ 180g/mol = 8.89 × 10-³mol

P × 0.250 = 0.00889 × 0.08206 × 298

0.25P = 0.217

P = 0.217/0.25

P = 0.869atm

Therefore, the osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

Learn more about osmotic pressure at: brainly.com/question/10046758

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