Answer:
So, Luke and Sian has to increase the pH of the soil by adding base to it.
Explanation:
The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
- With increase in hydrogen ion concentration the pH value decreases.
- With decrease in hydrogen ion concentration the pH value increases.
The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.
Comparison of pH of soil:
= 5.0 < 6.5
= High hydrogen ion concentration > High hydrogen ion concentration
So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).
The pressure of the gas in the flask (in atm) when Δh = 5.89 cm is 1.04 atm
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Atmospheric pressure (Pa) = 730.1 torr = 730.1 mmHg
- Change in height (Δh) = 5.89 cm
- Pressure due to Δh (PΔh) = 5.89 cmHg = 5.89 × 10 = 58.9 mmHg
- Pressure of gas (P) =?
<h3>How to determine the pressure of the gas</h3>
The pressure of the gas can be obtained as illustrated below:
P = Pa + PΔh
P = 730.1 + 58.9
P = 789 mmHg
Divide by 760 to express in atm
P = 789 / 760
P = 1.04 atm
Thus, the pressure of the gas when Δh = 5.89 cm is 1.04 atm
Learn more about pressure:
brainly.com/question/22523697
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Missing part of question:
See attached photo
Answer:
Answer 9 - 100 joules energy was at the producer level
Answer 10 - Remaining energy is used in metabolism
Explanation:
Answer 9
The energy at each trophic level is only 10% of the energy at its previous trophic level.
The energy at producer level is X
% of 
Joules
Joules
Answer 10
Because the remaining 90% energy is utilized by the producer for its metabolism
Answer:
pH = 12.52
Explanation:
Given that,
The [H+] concentration is 
.
We need to find its pH.
We know that, the definition of pH is as follows :
![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
Put all the values,
![pH=-log[3\times 10^{-13}]\\\\pH=12.52](https://tex.z-dn.net/?f=pH%3D-log%5B3%5Ctimes%2010%5E%7B-13%7D%5D%5C%5C%5C%5CpH%3D12.52)
So, the pH is 12.52.
