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Mariana [72]
3 years ago
6

How is the electrostatic force affected when the magnitude of a charge is doubled?

Physics
1 answer:
BaLLatris [955]3 years ago
4 0
The magnitude of the electrostatic force between two charges is given by:
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We can see that the magnitude of the force is directly proportional to the charges. This means that when one of the charges is doubled, the magnitude of the electrostatic force will double as well, so the correct answer is
A) <span>The magnitude of the electrostatic force doubles</span>
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Answer:

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Explanation:

Given,

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Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }  m

Where,

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Substituting the values in the above equation

                   R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }  

                                          = 132.72  m

Hence, the car lands at a distance, R_{max}= 132. 72 m            

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