Business owners must consider the products mission statement, a unique brand, the timing, the packaging, promotion, the audience.
To create a product you first need a problem then a solution. So if the problem is that water bottles aren’t holding enough water, the solution would be to create bigger yet lighter water bottles.
Let’s say you are to create a water bottle that is sturdier than others and can hold more water but weigh less. You would first consider the target audience. People that exercise and are into fitness would find the product more useful. So many making changes to the product to better fit their needs will help. Next the promotion and timing . It would be best to release the product near New Years since that’s when most people go to gyms. This will allow your product to reach a greater target audience and have more sales. Also testing your bottle to make sure it’s up to what you’re proving and so on.
Answer:
0.501 L
Explanation:
To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".
V∝ 1/P
V= K/P
VP=K
Here the K is proportionality constant.
so,
P1V1 = P2V2
P= pressure
V= volume
Given data:
P1= 1 atm
V1= 461 mL
P2= 0.92 atm
V2= ? (L)
To solve this problem we have to convert the mL into L first.
1 L = 1000 mL
461/1000= 0.461 L
Now we will put the values in the equation,
P1V1 = P2V2
V2= P1V1/ P2
V2= 1 atm × 0.461 L / 0.92 atm
V2= 0.501 L
Answer : The density of a sample of chlorine gas is, 12.59 g/L
Explanation :
To calculate the density of chlorine gas we are using ideal gas equation.

where,
P = pressure of chlorine gas = 4.5 atm
V = volume of chlorine gas = 12.6 L
n = number of moles of chlorine gas
w = mass of chlorine gas
R = gas constant = 0.0821 L.atm/mol.K
T = temperature of chlorine gas = 
M = molar mass of chlorine gas = 71 g/mol
Now put all the given values in the above formula, we get:



Therefore, the density of a sample of chlorine gas is, 12.59 g/L
Answer:
Becomes 1/4 as much
Explanation:
If a and b are directly proportional, this means we may write an equality between them if some proportionality constant, k, is included, so that:

The equation shows that:

And since k is a constant, this would imply that increasing a by some fraction would also require b to increase by the same fraction.
In the context of this problem, we're given that a becomes 1/4 as much, meaning b should also become 1/4 as much to keep the same proportionality constant, k.
Answer:
Like dissolves like" is an expression used by chemists to remember how some solvents work. It refers to "polar" and "nonpolar" solvents and solutes. Basic example: Water is polar. Oil is non polar. ... Like dissolves like, that means polar dissolves polar, so water dissolves salt.
Explanation: