Answer:
C. equal to, elements, products
Explanation:
I took a quiz and it said this was right
Answer:
It uses sodium nitrate, so that the nitrate group reacts with silver and precipitates as a salt, thus forming silver nitrate
And as for the precipitation of barium, I would use sodium sulfate, since we would use the nitrate group, barium nitrate would form, which is very dangerous and is considered high risk.
Explanation:
All the compounds that we name are reactions where as a product they give salts that are highly complex, where they are solid at room temperature, precipitate and are whitish in color.
These salts so that they precipitate it is important that they are in supersaturation since otherwise they will be in constant dynamism dissolving with the water, since they are soluble in them and the decantation will not be perceived at the naked eye of the human eye.
In a 0.20 M solution, a weak acid is 3.0% dissociated, the value of
H₃O⁺ =9.19 × 10⁻² OH⁻ = 1.09 × 10⁻¹³, pH =1.04 , pOH = 12.96
<h3>What is pH?</h3>
The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.
The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.
⇒pH = -log(
)
Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.
Lets find [H₃O⁺]
Because 12.5% of the weak acid dissociated, 12.5% of the concentration of the weak acid also produced H3O.
H₃O = HA × 0.125
= 0.735 M × 0.125
= 9.19 × 10⁻²
Lets find [OH⁻]
Using the Kw = 1.0 × 10⁻¹⁴
Kw = [H₃O⁺][OH⁻]
[OH⁻] = Kw / [H₃O⁺]
= 1.0 × 10⁻¹⁴ / 9.19 × 10⁻²
= 1.09 × 10⁻¹³
Lets find pH
pH = -log[H₃O⁺]
= -log(9.19 × 10⁻²)
= 1.04
Lets find pOH
Using pH +pOH = 14
pH +pOH = 14
pOH = 14 - pH
= 14 - 1.04
= 12.96
Learn more about pH
brainly.com/question/12609985
#SPJ4