Answer:
<em>In the given case, the SALT of the image is,</em>
<em />
<em>Size - Magnified</em>
<em />
<em>Altitude - Inverted</em>
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<em>Location - Behind the center of curvature</em>
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<em>Type - Real</em>
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<em>The diagrammatic representation of the image is</em>
<em />
<em />
<em />
<em />
Where F is force, m is mass and a is acceleration.
Hope this helps.
r3t40
Answer:
A. 7.1m
B. 3.55m/s
C. 1.775m/s^2
Explanation:
First step is to identify given parameters;
Ball 1: m₁ = 0.5kg, u (initial velocity) =0, t = 2seconds
Ball 2: m₂ = 0.25kg, u = 15m/s, t = 2seconds
<u>Second step:</u> we determine the y-coordinate of ball 1 after 2 seconds, using the equation of motion under gravity as shown below;
Recall, that the ball was thrown from a height of 25m, total y-coordinate of ball 1 after 2 seconds becomes 25m +(-19.6m)
[tex]y_{1} = 5.4m[/tex]
<u>Third step</u>: we determine the y-coordinate of ball 2 after 2 seconds
<u>Fourth step: </u>we determine the y-component of the center mass of the two balls
y = 7.1m
<u>Fifth step:</u> we solve B part of the question; velocity of the center mass of the two balls
velocity = 3.55m/s
<u>Sixth step:</u> we solve C part of the question; acceleration of the center mass of the two balls
acceleration = 1.775 m/s^2