Question

During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300 m/s2 (about 30 times free-fall acceleration called 30 g). The fuel burned for 7.0 s . Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.

Answer 1

The equation that we can use in this case is:

y = v0 t + 0.5 a t^2

where, y is the height, v0 is initial velocity = 0, t is time, a is acceleration so that:

y = 0 + 0.5 * (300 m/s^2) * (7 s)^2

y = 7350 m