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4vir4ik [10]
3 years ago
13

Assuming motion is on a straight path, what would result in two positive components of a vector?

Physics
2 answers:
Aliun [14]3 years ago
3 0
Answer: option <span>A) a train moving north of east at an angle of 25°
</span>

Explanation:

1) You need to choose your axis. In this case North is vertical and positive, South is vertical and negative, East is horizontal and positive, and West is horizontal and negative.

2) The vector with the two positive components is a vector in the first quadrant (North and East). That is what North of East 25° means.

3) Regarding the other options:

<span>B) a bus moving North of East at an angle of 95°: since the angle is greater tnan 90° the vector is in the second quadrant: its horizontal component is negative.
</span>
<span /><span>
</span><span> C) a boat moving South of West at an angle of 40°: this is in the third quadrant: the two components are negative.</span>
<span /><span>
</span><span> D) a car moving south of west at an angle of 10°: as in the option C), this is in the third quadrant: the two components are negative.
</span>

avanturin [10]3 years ago
3 0

A.

Two positive components means that the vector should lie in the first quadrant and not be parallel to the x or y axis; the only option that satisfies this is A.

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A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.1 m/s , a typical raindrop speed. how fast
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When two positive charges are brought close together, what happens to the
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Why will a sheet of paper fall slower than one that is crumbled into a ball
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4 0
3 years ago
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A negative charge of - 8.0 x 10^-6 C exerts an attractive force of 12 N on a second charge that is
Umnica [9.8K]

Answer:

<h2>Magnitude of the second charge is -4.17*10^{-7}C</h2>

Explanation:

According to columbs law;

F = kq1q2/r^{2}

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q1 and q2 are the charges

let q1 = - 8.0 x 10^-6 C

q2=?

r is the distance between the charges = 0.050m

k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²

On substituting the given values

12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²

Cross multiplying

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4 years ago
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