Answer:
D. It is relatively inert.
Explanation:
Answer:
Polarizing angle, 
Given:
Critical angle, 
Solution:
Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:
(1)
where
= refractive index of zirconia
From eqn (1):
Now, the angle of polarization is given by:
tan
Therefore,
Explanation :
We know that the resistance of the wire is given by :
Where
is the resistivity
l is the length of the wire
A is the area of the wire.
Another factor on which the resistance of wire depends is temperature. It is given by :
![R=R_{ref}[1+\alpha (T-T_{ref})]](https://tex.z-dn.net/?f=R%3DR_%7Bref%7D%5B1%2B%5Calpha%20%28T-T_%7Bref%7D%29%5D)
So, it is clear that the resistance of the wire is directly proportional to the temperature. It we want to decrease the resistance of the piece, its temperature should be decreased.
So, the correct option is (3) " decreasing the wire’s temperature ".
The power supply isn't connected
Answer:
E. Kepler's second law says the planet must move fastest when it is closest, not when it is farthest away.
Explanation:
We can answer this question by using Kepler's second law of planetary motion, which states that:
"A line connecting the center of the Sun with the center of each planet sweeps out equal areas in equal intervals of time"
This means that when a planet is further away from the Sun, it will move slower (because the line is longer, so it must move slower), while when the planet is closer to the Sun, it will move faster (because the line is shorter, so it must move faster).
In the text of this problem, it is written that the planet moves at 31 km/s when is close to the star and 35 km/s when it is farthest: this is in disagreement with what we said above, therefore the correct option is
E. Kepler's second law says the planet must move fastest when it is closest, not when it is farthest away.
