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Nadusha1986 [10]
3 years ago
7

2.15g of an unknown gas at 51c and 1.00 atm is stored in a 2.95 L flask

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0
<span>MM = [(2.15)(0.08206)(344)]/[(1.1)(1.75)] = 31.53 g/mol Remember to convert temperature to Kelvin.</span>
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