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3 years ago

9

NEED HELP NOW 100 POINTS 5 pictures to answer WILL MARK BRAINLIEST ANSWER!!!!!!!!! on question 9 and 10 you have to write a writ

ten short response.

2 answers:

Sholpan [36]3 years ago

5 0

1-a

2-c

3-a

4-b

hope it helps you bye

irga5000 [103]3 years ago

3 0

Ok number one is A number 2 is C number 3 is A number 4 is B hope it helps

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The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w

tangare [24]

Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

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3 years ago

Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H2(g) + N2(g) → 2NH3(

sergey [27]

Answer:

Explanation:

The equation of the reaction is given as:

3H₂ + N₂ → 2NH₃

Given parameters:

Number of moles of NH₃ = 8moles

Number of moles of H₂ = ?

Number of moles of N₂ = ?

Solution

From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:

To find the number of moles of H₂;

The equation shows that:

2 moles of NH₃ were produced using 3 moles of H₂

therefore: 8 moles of NH₃ will be produced by $\frac{8 x 3}{2}$ = 12moles

So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.

To find the number of moles of N₂

The equation shows that:

2 moles of NH₃ were produced from 1 mole of N₂

8 moles of NH₃ would be produced from $\frac{8 x 1}{2}$ = 4moles of Nitrogen gas

Therefore, 4moles of nitrogen gas would be produced

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3 years ago