Answer:
Option-D (Piece of Wood) is the correct answer.
Explanation:
Density is related to mass and volume as,
Density = Mass / Volume
For Wood,
Density = 42.5 / 50
Density = 0.85
You can calculate remaining densities by yourself. Among all the density of Piece of Wood is the least.
Answer:
Hence the solids that should test to investigate the effects of cations on pH is
(Cation is Al 3+)
( Cation is Mg 2+)
( Cation is NH2+).
Explanation:
The solids in the following should you test to investigate the effects of cations on pH.
contains (Cation is Al 3+)
contains ( Cation is Mg 2+)
contains( Cation is NH2+ )
Answer:
See explanation
Explanation:
The question is incomplete but i will try to give you all the necessary guide that you need in order to answer the question.
When compounds are formed, atoms exchange valency. The valency of nitrogen is three while that of the metal is two. The exchange yields M3N2.
If the compound has been specifically mentioned to be a metal, then it must be a group two element. It could be any of Mg, Ca, Sr, Ba or Ra. I did not mention Be here because most of its compounds are covalent.
This will help you to answer the complete question.
The ratio which denotes the relation between the two different units is said to conversion factors.
According to conversion factors, the relation between calorie and kilojoule is given as, one Calorie is equal to 4.184 kJ.
1 Cal = 4.184 kJ
Now, according to above relation, convert 300 calories into kilojoules.
300 calories =
= 
Thus, kilojoules present in soda is equal to 
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
