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Ket [755]
3 years ago
10

A laser produces 17.0 mW of light. In 4.00 hr , the laser emits 6.04×1020 photons. What is the wavelength of the laser?

Chemistry
2 answers:
Vlad [161]3 years ago
5 0
The unit 'mW' means milliwatts. It is a unit of work. There are 1,000 milliwatts in a 1 Watt of work. In 4 hours, there are 14,400 seconds.

Work= Energy/time
17 mW * 1 W/1000 mW = Energy/(14,400 seconds)
Solving for energy,
Energy = 244.8 J
Energy/photon = 244.8 J/(6.04×10²⁰) = 4.053×10⁻¹⁹ J/photon

Using the Planck's equation:

E = hc/λ
where h = 6.626×10⁻³⁴ m²·kg/s, c = 3,00,000,000 m/s and λ is the wavelength

4.053×10⁻¹⁹ J/photon = (6.626×10⁻³⁴ m²·kg/s)(3,00,000,000 m/s)/λ
λ = 4.9×10⁻⁷ m or 49 micrometers


jarptica [38.1K]3 years ago
3 0

Answer:

λ = 490.81 nm

Explanation:

The first thing we need to do is use the correct units. Let's convert the mW to J/s.

1 Watt --------> 1 J/s

And we have 17 mW:

1 Watt --------> 1000 mW

Therefore, converting the mili watts to J/s we have:

17 mW * 1 J/s / 1000 mW = 0.017 J/s

Now, we have 4 hours, and in 1 hour we have 3600 seconds so:

t = 4 * 3600 = 14,400 s

Now, the expression to calculate the wavelength is the following:

E = hc/λ (1)

Where:

E: Energy emmited by the laser by photons (J)

h: Planck constant = 6.626x10⁻³⁴ J.s

c: speed of light = 3x10⁸ m/s

λ: wavelength (nm)

Now, we have the Power of the laser, but not the energy emmited by photons. Let's calculate that value:

E = 0.017 J/s * 14,400 s / 6.04x10²⁰

E = 4.05x10⁻¹⁹ J

Now that we have the value of Energy, we just solve for Lambda from (1) to get the wavelength:

λ = hc/E (2)

Now, all we have to do is replace the obtained values and solve for the wavelength:

λ = (6.626x10⁻³⁴ J.s * 3x10⁸ m/s) / 4.05x10⁻¹⁹ J

λ = 490.81x10⁻⁹ m

And to get this value to nanometers (The usual unit of wavelength):

1 m ------> 1x10⁹ nm

Therefore:

<h2><em><u>λ = 490.81 nm</u></em></h2>
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liberstina [14]
<span>How many mm are equal to 21 L? 

1 L = </span>1000000 mm

Convert:-

1000000 × 21 = <span>21000000

21 l = </span><span>21000000 mm

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8 0
3 years ago
If the K a Ka of a monoprotic weak acid is 7.3 × 10 − 6 , 7.3×10−6, what is the pH pH of a 0.40 M 0.40 M solution of this acid?
olga_2 [115]

Answer:

pH =3.8

Explanation:

Lets call the monoprotic weak acid HA, the dissociation equilibria in water will be:

HA + H₂O   ⇄ H₃O⁺ + A⁻    with  Ka = [ H₃O⁺] x [A⁻]/ [HA]

The pH is the negative log of the H₃O⁺ concentration, we know the equilibrium constant, Ka and the original acid concentration. So we will need to find the [H₃O⁺] to solve this question.

In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

                          HA                                   H₃O⁺                          A⁻          

Initial, M             0.40                                   0                              0

Change , M          -x                                     +x                            +x

Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

Ka = x² / (0.40 - x )

Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

7.3 x 10⁻⁶ = x² / 0.40  ⇒ x = √( 7.3 x 10⁻⁶ x 0.40 ) = 1.71 x 10⁻³

[H₃O⁺] = 1.71 x 10⁻³

Indeed 1.71 x 10⁻³ is small compared to 0.40 (0.4 %). To be a good approximation our value should be less or equal to 5 %.

pH = - log ( 1.71 x 10⁻³ ) = 3.8

Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

4 0
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Soloha48 [4]

The following Balanced Reaction will take place:

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In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction

<u>Amount of HCl required to completely react with 2 moles of Zn:</u>

Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn

<u>Identifying the Limiting Reagent:</u>

But we are only given 3 moles of HCl where we need 4 moles to completely react.

So, since HCl is in less amount, it is the Limiting Reagent

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A certain man needed 400N of force to pull a load through a distance of 150cm in 8s . Calculatell i) the work done by man ii) th
Igoryamba

Answer:

a) 600 J

b) 75 W

Explanation:

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a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

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Answer:

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