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alekssr [168]
3 years ago
12

Which of the following refers to applications and technologies that are used to gather, provide access to, and analyze data and

information to support decision-making efforts?
a) data
b) information
c) information technology
d) business intelligence
Physics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

d) business intelligence

Explanation:

 Business intelligence refers to applications and technologies that are used to gather, provide access to, and analyze data and information to support decision-making efforts. Business Intelligence uses technologies for the data analysis of business information to make strategic decision for enterprises. Common functions of business intelligence technologies include reporting, online analytical processing, analytics, data mining, process mining, complex event processing, business performance management, benchmarking, text mining, predictive analytics and prescriptive analytics.

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QUESTION 9
Alik [6]

Answer:

The answer is option a.

Hope this helps

4 0
3 years ago
The distance between 4 nodes (3 sections, 2 sections= wavelength) is 15.0cm. The frequency of the source is 10Hz. What's the spe
Natalija [7]

Answer:

the speed of the waves is 150 cm/s

Explanation:

Given;

frequency of the wave, f = 10 Hz = 10

distance between 4 nodes, L = 15.0 cm

The wavelength (λ) of the wave is calculated as follows;

Node to Node = λ/2

L = 2(Node to Node) = (4 Nodes) = 2 (λ/2) = λ

Thus, λ = L = 15.0 cm

The speed (v) of the wave is calculated as follows;

v = fλ

v =  10 Hz   x  15.0 cm

v = 150 cm/s

Therefore, the speed of the waves is 150 cm/s

7 0
2 years ago
PLS HELP! If you are given force and distance, you can determine power if you know (2 points)
Lisa [10]

Answer:

C. Time

Explanation:

6 0
3 years ago
Read 2 more answers
Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)
sergeinik [125]

v^2-{v_0}^2=2a(x-x_0)

dónde v es la velocidad de la esfera, v_0 es suya velocidad inicial, a=-g la aceleración debida a la gravedad, x la posición, y x_0 la posición inicial. Tomamos x_0=0\,\mathrm m a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)

\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

4 0
3 years ago
Find the number of electrons in the subshell with azimuthal quantum number l=2
steposvetlana [31]

Answer:

23 electrons

Explanation:

i just know because im a god

6 0
2 years ago
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