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yarga [219]
3 years ago
8

Why does a solution of acid and sodium thiosulfate go cloudy

Chemistry
1 answer:
klemol [59]3 years ago
4 0
The soulustion. turn cloudy due to the precipitation of Sulphur.
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If the concentration of the HCl used in your titration was 1.00 M and you used 23.68 mL to reach the endpoint, calculate the con
drek231 [11]

Answer: The concentration of the OH-, CB = 0.473 M.

Explanation:

The balanced equation of reaction is:

2HCl + Ca(OH)2 ===> CaCl2 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2 (from the balanced equation of reaction)

NB is the number of mole of base = 1 (from the balanced equation of reaction)

CA is the concentration of acid = 1M

CB is the concentration of base = to be calculated

VA is the volume of acid = 23.65 ml

VB is the volume of base = 25mL

Substituting

1×23.65/CB×25 = 2/1

Therefore CB =1×23.65×1/25×2

CB = 0.473 M.

6 0
3 years ago
Cations are formed by _____. gaining protons losing protons gaining electrons losing electrons
Ede4ka [16]
Cations are formed by losing electrons in the valence shell of atoms. There are more protons than electron ions making the atom more positive.
7 0
3 years ago
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Why do the densities of most substances increase when temperature decreases?
vlada-n [284]

This is because temperatures determine the kinetic energy of molecules of a substance, At lower temperatures the molecules have low kinetic energy hence the distance between molecules is not as large as when the kinetic energy is higher (because the molecules bombard less and with less kinetic energy). This means the substance can pack more molecules per volume at lower temperatures. The more the molecules per volume the higher the density.

6 0
3 years ago
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Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility
kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the  is given as:

Ca(OH)_2\rightarrow Ca^{2+}+2OH^-  

By stoichiometry of the reaction:

1 mole of  Ca(OH)_2 gives 1 mole of Ca^{2+} and 2 mole of OH^-

When the solubility of  Ca(OH)_2 is S moles/liter, then the solubility of Ca^{2+}  will be S moles\liter and solubility of OH^- will be 2S moles/liter.

K_{sp}=[Ca^{2+}][OH^{-}]^2

6.5\times 10^{-6}=[S][2S]^2

S=0.012M

Thus solubility of this compound in pure water is 0.012 M

5 0
3 years ago
Compared to pure water, an aqueous solution of calcium chloride has what?
V125BC [204]
It has a higher boiling point and a lower freezing point
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3 years ago
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