2 years ago

How to find final kinetic energy given height, mass, distance, and velocity.

Physics

1 answer:

Orlov [11]2 years ago

4 0

Answer:

KE = 1/2(m)(v^2)

Explanation:

You only need mass and velocity to find kinetic energy

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Make a quantitative graph for the motion of the two cars

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It would be helpful if you gave me a bit more information on what the cars speed is

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3 years ago

A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are

slava [35]

Answer:

The magnitude and direction of the acceleration of the particle is $a= 0.3296\ \hat{k}\ m/s^2$

Explanation:

Given that,

Mass $m = 1.81\times10^{-3}\ kg$

Velocity $v = (3.00\times10^{4}\ m/s)j$

Charge $q = 1.22\times10^{-8}\ C$

Magnetic field $B= (1.63\hat{i}+0.980\hat{j})\ T$

We need to calculate the acceleration of the particle

Formula of the acceleration is defined as

$F = ma=q(v\times B)$

$a =\dfrac{q(v\times B)}{m}$

We need to calculate the value of $v\times B$

$v\times B=(3.00\times10^{4}\ m/s)j\times(1.63\hat{i}+0.980\hat{j})$

$v\times B=4.89\times10^{4}$

Now, put the all values into the acceleration 's formula

$a =\dfrac{1.22\times10^{-8}\times(-4.89\times10^{4}\hat{k})}{1.81\times10^{-3}}$

$a= -0.3296\ \hat{k}\ m/s^2$

Negative sign shows the opposite direction.

Hence, The magnitude and direction of the acceleration of the particle is $a= 0.3296\ \hat{k}\ m/s^2$

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3 years ago

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Answer:

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3 years ago

Which statement correctly stated kepler's 3rd law of planetary motion?

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When you square the "year" of each planet and divide it by the cube of its distance, or axis from the sun, the number would be the same for all the planets

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3 years ago

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How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?

inysia [295]

1 coulomb of electric charge is carried by 6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

(2.0 x 10^20) / (6.25 x 10^18 x 10) sec = <em>3.2 seconds</em>

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3 years ago