By considering the reaction equation is: 5Br(aq)+BrO3(aq)+6H(aq)= 3Br2(aq)+3H2O(l) when the average rate of consumption of Br = 1.86x10^-4 m/s So from the reaction equation 5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So, ∴ 1.86x10^-4/5 = X / 3 ∴X = 1.1 x 10^-4 m/s ∴the average rate of formation of Br2 = 1.1x10^-4 m/s
