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ruslelena [56]
3 years ago
13

Two objects have unlike charges. How would the electric force between the two objects change as they are moved apart?

Physics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

as we move the two charges apart the attraction force between them will decrease in magnitude

Explanation:

As we know that two charges are unlike charges here so the force between them is attraction type of force

This force is given by Coulomb's law which is given as

F = \frac{kq_1q_2}{r^2}

so here this force is proportional to the product of two charges and inversely depends on the square of the distance between two charges

So here keeping the same magnitude of the charges we move them to large distance

So here the force between them must have decrease

So as we move the two charges apart the attraction force between them will decrease in magnitude

Karolina [17]3 years ago
4 0
Opposite charges repeal 
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How many types of electrical charge are there in all materials and what are the charges
JulsSmile [24]

There are two types of electric charges; positive and negative

- If you need more info than this let me know

- hope this helps

4 0
3 years ago
Practice questions, will mark brainliest!
andrew-mc [135]

Answer:

266.67Watts

Explanation:

Time = 2.5hr to seconds

3600s = 1hr

2.5hrs = 3600×2.5= 9000s

Force = 32N

Distance = 75km  to m

1000m = 1km

75km = 1000×75 = 75000m

Power = workdone / time

Work = force × distance

Therefore work = 32N × 75000m

Work = 2400000Nm

Power = work ➗ time

Power = 2400000Nm ➗ 9000s

Power = 266.67Watts

Watts is the S. i unit of power

I hope this was helpful, please mark as brainliest

4 0
3 years ago
A crane lifts a 1,750 kg mass using a steel cable whose mass per unit length is 0.88 kg/m. What is the speed of transverse waves
Sauron [17]

Answer:

139.6m/s

Explanation:

Calculate the tension first, T=m*g

mass(m): 1750kg, gravity(g): 9.8m/s^2

T= 1750*9.8

 =17150N

Then calculate the wave speed using the equation v = √ (T/μ)

v= √(17150N)/(0.88kg/m)

 =139.6m/s

4 0
3 years ago
An object is five focal lengths from a concave mirror.how do the object and image heights compare?
enot [183]

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

7 0
3 years ago
An experiment is conducted using 2 plants to determine if the amount of sunlight they receive affects how fast they grow. Which
Phantasy [73]

Greetings!

The correct answer choice is Choice 4.

<em>Why?</em>

In a scientific experiment the only thing being changed is the independent variable. Everything else should stay the same.

In this experiment, the independent variable is the amount of sunlight each plant should receive. <em>Here's a tip</em>- when looking for and independent variable look for whats being changed on purpose.

Hope this helps!

~Fluerie

4 0
3 years ago
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