Two objects have unlike charges. How would the electric force between the two objects change as they are moved apart?
2 answers:
Answer:
as we move the two charges apart the attraction force between them will decrease in magnitude
Explanation:
As we know that two charges are unlike charges here so the force between them is attraction type of force
This force is given by Coulomb's law which is given as
so here this force is proportional to the product of two charges and inversely depends on the square of the distance between two charges
So here keeping the same magnitude of the charges we move them to large distance
So here the force between them must have decrease
So as we move the two charges apart the attraction force between them will decrease in magnitude
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Answer:
the frequency of the second harmonic of the pipe is 425 Hz
Explanation:
Given;
length of the open pipe, L = 0.8 m
velocity of sound, v = 340 m/s
The wavelength of the second harmonic is calculated as follows;
L = A ---> N + N--->N + N--->A
where;
L is the length of the pipe in the second harmonic
A represents antinode of the wave
N represents the node of the wave
The frequency is calculated as follows;
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.