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3 years ago

Adding a catalyst to a reaction has an effect similar to

1 answer:

3 0

I will say increasing temperature but you dont have that option on your list, so I would take B. Increasing Concentration.

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Consider the following: Li(s) ???? 1???? (g) n LiI(s) ????H???? 222 ????292 kJ. LiI(s) has a lattice energy of ????753 kJ/mol. T

erma4kov [3.2K]

Answer : The heat of sublimation of Li(s) is 179.5 kJ/mole

Explanation :

The formation of lithium iodide is,

$Li^{1+}(g)+\frac{1}{2}I_2(g)\overset{\Delta H_L}\rightarrow LiI(s)$

$\Delta H_f^o$ = enthalpy of formation of lithium iodide

The steps involved in the born-Haber cycle for the formation of $LiI$ :

(1) Conversion of solid lithium into gaseous lithium atoms.

$Li(s)\overset{\Delta H_s}\rightarrow Li(g)$

$\Delta H_s$ = sublimation energy of lithium

(2) Conversion of gaseous lithium atoms into gaseous lithium ions.

$Li(g)\overset{\Delta H_I}\rightarrow Li^{+1}(g)$

$\Delta H_I$ = ionization energy of lithium

(3) Conversion of molecular gaseous iodine into gaseous iodine atoms.

$I_2(g)\overset{\Delta H_D}\rightarrow 2I(g)$

$\frac{1}{2}I_2(g)\overset{\Delta H_D}\rightarrow I(g)$

$\Delta H_D$ = dissociation energy of iodine

(4) Conversion of gaseous iodine atoms into gaseous iodine ions.

$I(g)\overset{\Delta H_E}\rightarrow I^-(g)$

$\Delta H_E$ = electron affinity energy of iodine

(5) Conversion of gaseous cations and gaseous anion into solid lithium iodide.

$Li^{1+}(g)+I^-(g)\overset{\Delta H_L}\rightarrow LiI(s)$

$\Delta H_L$ = lattice energy of lithium iodide

To calculate the overall energy from the born-Haber cycle, the equation used will be:

$\Delta H_f^o=\Delta H_s+\Delta H_I+\frac{1}{2}\Delta H_D+\Delta H_E+\Delta H_L$

Now put all the given values in this equation, we get:

$-273kJ/mole=\Delta H_s+520kJ/mole+\frac{1}{2}\times 151kJ/mole+(-295kJ/mole)+(-753kJ/mole)$

$\Delta H_s=179.5kJ/mole$

Therefore, the heat of sublimation of Li(s) is 179.5 kJ/mole

6 0

3 years ago

In the design of a new building, a doorway is 2.45 ft above the ground. A ramp for the disabled, at an angle of 4.5 ° with the g

kkurt [141]

Answer:

Length of the ramp, l = 31.22 feet

Explanation:

It is given that,

A doorway is 2.45 ft above the ground, AB = 2.45 ft

Angle between the ground and the ramp is, $\theta=4.5^{\circ}$

Applying trigonometry,

$sin\theta=\dfrac{AB}{AC}$

$AC=\dfrac{AB}{sin\theta}$

$AC=\dfrac{2.45}{sin(4.5)}$

AC = 31.22 ft

So, the length of the ramp is 31.22 feet. Hence, this is the required solution.

3 0

3 years ago

90 points whats the equation for how fast something will be traveling before it hits the ground. How to do the equation PLEASE E

Varvara68 [4.7K]

given GPE=M*g*h

KE= 0.5*Mass *velocity squared

something falls n before it hits the ground,

by conservation of energy

GPE loss = KE gain

e.g. A 0.05 kg-coin is dropped from the top of a skyscraper that is 100 meters high.

so M=0.05, g=9.8m/s^2, h=100m

GPE loss=M*g*h=0.05*9.8*100

=49J

KE gain=0.5*Mass *velocity squared=GPE loss

0.5*0.05*velocity squared=49

velocity squared=49/0.5/0.05=1960

velocity=sqrt(1960)=44.27m/s

7 0

3 years ago

Read 2 more answers

Please help!!!

krek1111 [17]

The answer is influenced

6 0

3 years ago

Read 2 more answers

In an experiment to determine the fractal dimension of crumpled newspaper, mass and radius were plotted on log-log paper. Select

777dan777 [17]

Answer:

fractal dimension is 0.1092

Explanation:

given data

vertical distance V = 44 mm = 0.044 m

horizontal distance H = 30 mm = 0.030 m

to find out

fractal dimension

solution

we will apply here fractal dimension formula that is

logV = ( 1 - fractal dimension) logH ...................a

put here all value in equation a

we get

fractal dimension = 1 - $\frac{logV}{logH}$

fractal dimension = 1 - $\frac{log0.044}{log0.030}$

fractal dimension = 1 - $\frac{-1.35654732351
}{-1.52287874528
}$

fractal dimension = 0.1092217

so fractal dimension is 0.1092

8 0

3 years ago