All categories

2 years ago

What major advantage does a parallel circuit have over a series circuit? plz Answer ASAP

2 answers:

4 0

A parallel circuit has more than one current path between the battery terminals. If one path becomes blocked or cut, then current continues to flow through the other [one or more] paths. This may be an advantage in some types of circuits ... for example, in a string of Christmas-tree lights.

NOTE: If you have a list of choices and you have to select the 'correct' or 'best' choice, but you decide to just dump the question onto Brainly and get the answer from somebody else, you have to realize that nobody else can help you choose the correct one if you don't let them see what the choices <em>are.</em> The list of choices is a PART of the question. When you post the question for other people to see, you've GOT TO post the choices too.

IceJOKER [234]2 years ago

3 0

it is easier to connect cpts by going across the in parllel rather than breaking a conn and reforming it

You might be interested in

A net force of 100 n is moving a mass with an acceleration of 5 m/s2. what is the mass of the object? 0.05 kg 20 kg 95 kg 500 kg

dezoksy [38]

F = ma
100n = m(5m/s^2)
100/5 = 20

6 0

3 years ago

Read 2 more answers

a jet plane traveling 1890 km/h pulls out of a dive by moving in an arc of radius 5.20km. what is planes acceleration in g's

Andrew [12]

Answer:

$53 m/s^2$

Explanation:

Unit conversions:

1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s

5.2 km = 5200 m

Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:

$a = \frac{v^2}{r}$

where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc

$a = \frac{525^2}{5200} = 53m/s^2$

7 0

3 years ago

A uniform meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 5 s. The meter stick

rewona [7]

Answer:

The new time period is $T_2 = 3.8 \ s$

Explanation:

From the question we are told that

The period of oscillation is $T = 5 \ s$

The new length is $l_2 = 0.76 \ m$

Let assume the original length was $l_1 = 1 m$

Generally the time period is mathematically represented as

$T = 2 \pi \sqrt{ \frac{ I }{ mgh } }$

Now I is the moment of inertia of the stick which is mathematically represented as

$I = \frac{m * l^2 }{12 }$

$T = 2 \pi \sqrt{ \frac{ m * l^2 }{12 * mgh } }$

Looking at the above equation we see that

$T \ \ \ \alpha \ \ \ l$

=> $\frac{ T_2 }{T_1} = \frac{l_2}{l_1}$

=> $\frac{ T_2}{5} = \frac{0.76}{1}$

=> $T_2 = 3.8 \ s$

3 0

3 years ago

For a satellite of mass mS in a circular orbit of radius rS around the Earth, determine its kinetic energy, K . Express your ans

agasfer [191]

Since it is asking you to find the kinetic energy in relation to the mass, radius, mechanical energy (total energy), and constants, you will need to setup an equation first to "find" the Mechanical Energy, so that we can then solve for the kinetic energy, as from my experience with high school physics, there is only the graviational potential energy equation and force in relation to celestial bodies.

Knowing the ME is the total energy, we add up the energies of the system. Since it is being influenced by the Earth, as per the problem stating the satellite has circular orbit around the Earth, we know there is gravitational potential. Since it is orbiting, we can assume some type of velocity. Nothing else that we need to worry about should be occuring at this level of physics, leaving you with

ME= Ug+K

from here we solve for K, as plugging in could get confusing and messy at the moment.

ME-Ug=K

now using the equations presumably given in class, if not then using this equation, we can find the Ug

Ug=(-(Gm*M)/r) note that M is the mass of the Earth and m is the satellite

this should give us

ME-(-(GmM)/r)=K

since there is a negative being subracted, we can change that to

ME+(GmM)/r=K

I believe this should be fine, as the Earth's mass is constant, but if not, then all you need to figure left is how to get rid of the M in the equation, as the rest of the terms and constants are for sure within the requirements.

8 0

2 years ago

1. A brick and a peanut are dropped of the roof of a house at the same time, which

iris [78.8K]

Answer:

It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give

Explanation:

3 0

2 years ago