Answer:
amount of work done, W = 549.36 kJ
Given:
mass of a car engine, m = 2500 kg
initial velocity, u = 45 mph
final velocity, v = 65 mph
1 mile = 1609
Solution:
We know that 1 hour = 3600 s
Now, velocities in m/s are given as:
u = 45 mph = = 20.11 m/s
v = 65 mph = = 29.05 m/s
Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:
W =
W =
W =
W = 549.36 kJ
he basket ball diameter used by NBA men players is around 9.55 inches
So diameter = 9.55 inch = 0.243 m
So radius of basket ball = 0.1215 m
Volume ,
So volume of basket ball used by men NBA players = 7.5 L
Answer:
F₁ / F₂ = exp (-Q_{v} / k) exp [(T₂-T₁) / T₁T₂]
Q_{v} = -k ΔT / T₁T₂ ln (F₁ / F₂)
Explanation:
The Boltzmann equation for vacancies is
n = n₀ exp (-Eₙ /kT)
Where n and n₀ are the number of current and maximum vacancies, respectively, Eₙ is the activation energy (), K the Boltzmann constant and T the absolute temperature
The fraction is
F = n / n₀ = exp (- Q_{v} / kT)
Let's apply this equation to our case
For temperature T = T₁
F₁ = exp (-Qv / k T₁)
For temperature T = T₂
F₂ = exp (-Qv / kT₂)
The ratio of the vacancy fraction is
F₁ / F₂ = exp (-Q_{v} / k T₁) / exp (- Q_{v} / k T₂)
F₁ / F₂ = exp (-Q_{v} / k) exp [(T₂-T₁) / T₁T₂]
In general, the activation energy is sought by clearing this equation
Q_{v} = -k ΔT / T₁T₂ ln (F₁ / F₂)