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snow_lady [41]
4 years ago
9

The law of conservation of momentum states that a. the total initial momentum of all objects interacting with one another usuall

y equals the total final momentum. b. the total initial momentum of all objects interacting with one another does not equal the total final momentum. c. the total momentum of all objects interacting with one another is zero. d. the total momentum of all objects interacting with one another remains constant regardless of the nature of the forces between the objects.
Physics
2 answers:
Inessa [10]4 years ago
8 0
The law of conservation of momentum states that a.
The total initial momentum of all objects interacting with one another usually equals the total final momentum. This will just mean that the energy acquired is equal to energy given by an object.
dalvyx [7]4 years ago
5 0
According to the Law of conservation of momentum, the total momentum of the system before and after the collision remains same. The momentum may transfer from one object to another as a result of the impact, but the overall momentum of the system remains same.

So, the correct answer is option a.
The total initial momentum of all objects interacting with one another usually equals the total final momentum.
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Crystalline solids must have a specific, orderly arrangement of atoms to be considered so.
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In an electrolytic cell, to which electrode will a positive ion migrate and undergo reduction? the anode, which is negatively ch
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The reaction of reduction always undergoes with the cathode, the positive ion will migrate towards the cathode with the negative charge whilst the anode always has oxidation reaction. These two types of reaction does not change.
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Read 2 more answers
A point charge with charge q1 = 3.40 μC is held stationary at the origin. A second point charge with charge q2 = -4.90 μC moves
expeople1 [14]

Answer:

-0.79 J

Explanation:

We are given that

q_1=3.4\mu C=3.4\times 10^{-6} C

1\mu C=10^{-6} C

q_2=-4.9\mu C=-4.9\times 10^{-6} C

x_1=0.125,y_1=0

x_2=0.280,y_2=0.235

We have to find the work done by the electric force on the moving point charge.

r_1=\sqrt{x^2_1+y^2_1}=\sqrt{(0.125)^2+0}=0.125

r_2=\sqrt{(0.280)^2+(0.235)^2}=0.366

Work done,W=kq_1q_2(\frac{1}{r_1}-\frac{1}{r_2})

Where k=9\times 10^9

Using the formula

W=9\times 10^9\times 3.4\times 10^{-6}\times(-4.9\times 10^{-6})(\frac{1}{0.125}-\frac{1}{0.366})

W=-0.79 J

5 0
4 years ago
How many sandwiches were made in the hour?
S_A_V [24]

Answer:

25

Explanation:

simple facts.

7 0
3 years ago
A test charge of 13 mC is at a point P where an external electric field is directed to the right and has a magnitude of 4 3 106
LenKa [72]

Answer:

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.

Explanation:

From coulomb's law, F = Eq

Thus,

F = E₁q₁

F = E₂q₂

Then

E₂q₂ = E₁q₁

E_2 = \frac{E_1q_1}{q_2}

where;

E₂ is the external electric field due to second test charge = ?

E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C

q₁ is the first test charge = 13 mC

q₂ is the second test charge = 23 mC

Substitute in these values in the equation above and calculate E₂.

E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.

However, the direction of the external field is still to the right.

8 0
3 years ago
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