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snow_lady [41]
4 years ago
9

The law of conservation of momentum states that a. the total initial momentum of all objects interacting with one another usuall

y equals the total final momentum. b. the total initial momentum of all objects interacting with one another does not equal the total final momentum. c. the total momentum of all objects interacting with one another is zero. d. the total momentum of all objects interacting with one another remains constant regardless of the nature of the forces between the objects.
Physics
2 answers:
Inessa [10]4 years ago
8 0
The law of conservation of momentum states that a.
The total initial momentum of all objects interacting with one another usually equals the total final momentum. This will just mean that the energy acquired is equal to energy given by an object.
dalvyx [7]4 years ago
5 0
According to the Law of conservation of momentum, the total momentum of the system before and after the collision remains same. The momentum may transfer from one object to another as a result of the impact, but the overall momentum of the system remains same.

So, the correct answer is option a.
The total initial momentum of all objects interacting with one another usually equals the total final momentum.
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1500 kg wrecking ball traveling at a speed of 3.5 m/s hits a wall that does not crumble but is pushed back 75 cm. If the wreckin
Rudiy27

Answer:

The size of the force that pushes the wall is 12,250 N.

Explanation:

Given;

mass of the wrecking ball, m = 1500 kg

speed of the wrecking ball, v = 3.5 m/s

distance the ball moved the wall, d = 75 cm = 0.75 m

Apply the principle of work-energy theorem;

Kinetic energy of the wrecking ball = work done by the ball on the wall

¹/₂mv² = F x d

where;

F is the size of the force that pushes the wall

¹/₂mv² = F x d

¹/₂ x 1500 x 3.5² = F x 0.75

9187.5 = 0.75F

F = 9187.5 / 0.75

F = 12,250 N

Therefore, the size of the force that pushes the wall is 12,250 N.

7 0
3 years ago
Suppose that on earth you can throw a ball vertically upward a distance of 1.20 m. Given that the acceleration of gravity on the
tatuchka [14]

Answer:

7.04 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement on Earth = 1.2 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

a = Acceleration due to gravity Earth= 9.81 m/s²

Accelration going up is considered as negetive

Initial Velocity of the ball

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 1.2-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 1.2}\\\Rightarrow u=4.85\ m/s

Assuming that the ball is thrown with the same velocity on the Moon, displacement of the ball is

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-4.85^2}{2\times -1.67}\\\Rightarrow s=7.04\ m

The displacement of the ball on the moon is 7.04 m

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3 years ago
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ira [324]
According to Newton's 2nd law of motion:
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Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/s^{2} = 13.8 N
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3 years ago
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<span>When an object is forced into resonance vibrations at one of its natural frequencies, it vibrates in a manner such that a standing wave is formed within the object. ... such patterns are only created within the medium at specific frequencies of vibration.</span>
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