Question

Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16.0 mL of CO?

Answer 1

Answer:

$V_{CO_2}=16.0mL$

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

$n_{CO}V_{CO}=n_{CO_2}V_{CO_2}$

Thus, solving for the yielded volume of carbon dioxide we obtain:

$V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL$

Best regards.