The term amphoteric describes a substance that can act as both an acid and a base.
1. carbon dioxide is a gas at low temperatures at mars because in the oxidizing environment organic compounds are oxidized to form carbon dioxide.
2. The 1 electron in outermost shell of Na is shared with 7 electrons of outermost shell of chlorine giving neutral charge on compound.
3. Electrostatic force of attraction is between the metal and non-metal.
4. When metal and non metal exchange electrons to form a neutral or no charge compound it is said to have form ionic bonds.
Explanation:
1. Temperature at Mars is very low -80 Fahrenheit (-60 degrees) because water is not present in the planet. Carbon dioxide is abundant in Mars. The atmosphere is oxidizing at Mars which oxidizes the organic compounds and forms carbon dioxide.
2. NaCl combines by sharing of electrons forming ionic bonding. Different atoms of the different element share electrons to form ionic bonds. Such bond is formed when electrons is transferred between the atoms. In the NaCl, Na has 1 electron (electropositive) in its outer shell and chlorine has 7 electrons (electronegative). Both share the electrons getting their octet complete and a neutral charge on the compound formed.
3. Electrostatic force of attraction is between the metal and non-metal when bond is formed. The ionic bonds is formed between metal and non metals when electron exchange takes place. The electrostatic force is the attraction between two opposite charges on the ion.
4. When a metal and non metal exchange electrons in which metal is electropositive and non metal is electronegative the bonds form is called ionic bond. The electron is transferred from metal to non metal and thus giving neutral charge on the compound i.e. the outer shell has its octet complete.
We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal
Answer:
pressure of gas are constant describe the relationship between moles and temprature
Answer:
No the substance is not water.
Explanation:
The balance chemical equation for the decomposition of water is as follow;
2 H₂O = 2 H₂ + O₂
Step 1: <u>Calculate moles of H₂O;</u>
Moles = Mass / M.Mass
Moles = 5.0 g / 18.01 g/mol
Moles = 0.277 moles of H₂O
Step 2: <u>Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:</u>
According to equation,
2 moles of H₂O produced = 1 mole of O₂
So,
0.277 moles of H₂O will produce = X moles of O₂
Solving for X,
X = 0.277 mol × 1 mol / 2 mol
X = 0.138 moles of O₂
Also,
According to equation,
2 moles of H₂O produced = 2 mole of H₂
So,
0.277 moles of H₂O will produce = X moles of H₂
Solving for X,
X = 0.277 mol × 2 mol / 2 mol
X = 0.227 moles of H₂
Step 3: <u>Calculate Mass of O₂ and H₂ as;</u>
For O₂:
Mass = Moles × M.Mass
Mass = 0.138 mol × 31.99 g/mol
Mass = 4.44 g of O₂
For H₂:
Mass = Moles × M.Mass
Mass = 0.227 mol × 2.01 g/mol
Mass = 0.559 g of H₂
Conclusion:
From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.
