Please help me with this physics question!

Ilya and Anya each can run at a speed of 7.50 mph and walk at a speed of 4.00 mph. They set off together on a route of length 5.

r-ruslan [8.4K]

Answer:

$T_A=0.93hours$

$S_A=5.23mph$

$T_l=0.87hour$

Explanation:

From the question we are told that

Run speed of Ilya and Anya $S_r=7.50mph$

Walk speed of Ilya and Anya $S_w=4.00mph$

Total distance $T_d=5.00miles$

Anya Walks 1/2d and runs 1/2d

ilya walks 1/2t and runs 1/2d

Generally the distance walked by Ilay k is mathematically given by

Since ilya walks 1/2t and runs 1/2t

Therefore

$\frac{k}{4}=\frac{5-k}{7.5}$

$k=1.7miles$

Therefore llay runing distance is m

$m=5-1.7\\m=3.3mile$

a)Generally the Time walked by Anya $T_A$ is mathematically given by

Anya Walks 1/2d and runs 1/2d

Therefore

$t=\frac{2.5}{4.}$

$t_1=0.6hours$

$t=\frac{2.5}{7.5}$

$t_2=0.33hours$

$T_A=0.6+0.33\\$

$T_A=0.93hours$

b)Generally the average speed of Anya S_A is mathematically given as

$S_A=\frac{Distance}{T_t}$

$S_A=\frac{5.0}{0.93}$

$S_A=5.23mph$

Generally the time taken b y llay $T_l$ is mathematically given by

$T_l=2t$

$T_l=2*(\frac{1.7}{4})$

$T_l=0.87hour$

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If the original coordinates of point Q are (A, B) and
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