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3 years ago

13

A 100-m long transmission cable is suspended between two towers. If the mass density is 2.01 kg/m and the tension in the cable i

s 3.00 x 104 N, what is the speed of transverse waves on the cable

1 answer:

Inga [223]3 years ago

3 0

Answer:

The speed is $v =122.2 \ m/s$

Explanation:

From the question we are told that

The length of the wire is $L = 100 \ m$

The mass density is $\mu = 2.01 \ kg/m$

The tension is $T = 3.00 *10^{4} \ N$

Generally the speed of the transverse cable is mathematically represented as

$v = \sqrt{\frac{T}{\mu} }$

substituting values

$v = \sqrt{\frac{3.0 *10^{4}}{2.01} }$

$v =122.2 \ m/s$

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A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flip

Artemon [7]

It will take the quarter 0.151 seconds to reach the ground.

<u>Given the following data:</u>

Height = 1.45 meters

Initial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

$S = ut + \frac{1}{2} at^2$

Where:

S is the height or distance covered.

u is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting the values into the formula, we have;

$1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0$

The standard form of a quadratic equation is:

$ax^2 + bx + c = 0$

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

$x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}$

Substituting the values, we have;

$t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}$

<em>Time, t = 0.151 seconds.</em>

Therefore, it will take the quarter 0.151 seconds to reach the ground.

Read more: brainly.com/question/8898885

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Lunna [17]

Answer: $3.79 m/s^2$

Explanation:

Given

Mass $M=9.5 kg$

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