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Rina8888 [55]
3 years ago
12

Students in a lab used a hot plate to boil water. Which of the following illustrations best represents the change in the movemen

t of particles as the temperature of the water increases?

Chemistry
1 answer:
Digiron [165]3 years ago
6 0

The second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.

<u>Explanation:</u>

The second option perfectly represents the boiling of water. As when the temperature is increased, the water molecules gain energy to move faster, thus their kinetic energy of the atoms will be more. This will lead to more freely movement of all the atoms of the water.

And as boiling leads to transformation from liquid state to gaseous state, so the increase in the distance between atoms and molecules occurs in the gaseous state. Thus, the second illustration is best suitable for representing the boiling of water.

As on increasing temperature of the water, the distance between the molecules is increasing in the second illustration while the other illustration shows the decrease in the distance between the molecules. So, the second illustration is the best representation of the change in the movement of particles as the temperature of the water changes.

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A ----------------- is a repeating pattern of positive and negative ions.
Dennis_Churaev [7]
That would be ionic lattice.
4 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
3 years ago
Anyone know ?? I need help with this
nevsk [136]

Answer:

A

Explanation:

Because the amount of electrons in the outer shell can be a maximum of 8

Hope this helps

6 0
3 years ago
What is the element present for copper
amm1812

Copper is an brown-orange color which it's atomic number is 29. With high thermal and electricity conductivity with it's smooth surface.

8 0
3 years ago
What is the endpoint of a titration?Select one:When there is no acid and all base.When the amount of acid and base are equal.Whe
user100 [1]

Answer:

The correct option is: When the amount of acid and base are equal

Explanation:

Titration is an analytic method that is used to determine the concentration of an<em> unknown solution</em>, called <em>titrand</em>.

In this method, standard solution of known concentration, called <em>titrant</em>, is taken in the burette and added drop-wise to the titrand solution in the flask, until the endpoint is reached.

In case of an acid-base titration, a <em>pH indicator</em> is used, which changes the color of the solution when the endpoint is reached.

<u>The </u><u>endpoint</u><u> indicates the </u><u>equivalence point</u><u> of an acid-base titration, where the </u><em><u>concentration of the acid and base is equal</u></em><u>. </u>

<u>Therefore, the </u><u>correct option</u><u> is: </u><u>When the amount of acid and base are equal</u>

3 0
3 years ago
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