Answer:
Tresca FOS ,N=4.49
Von mises theory FOS N=4.27
Explanation:
Cross sectional area of shaft A=
Bending stress =101.91 MPa (M=10 KN-m)
Shear stress =40.76 MPa (T=8 KN-m)
Axial stress=19.23 MPa
Now find the principle stress
Now put the values
From tresca theory
N=4.49
From Von mises theory
N=4.27
Answer:
C. Horizontal
Explanation:
The type of cylinder arrangement that is shown in the figure is "Horizontal"
The arrangement is actually horizontal which is known to be horizontally opposed engine. Such engine is known as flat engine. It's a piston engine that has the cylinders located on either side of a crankshaft. It is usually located at the central crankshaft. This type of engine has performance advantage over others.
Answer:
40.7 m
Explanation:
Let point 1 represent the surface of the water, point 2 be the top of the water trajectory and the reference be the bottom of the tank. Hence:
Answer:
Explanation:
Given that
Load is uniformly distributed load and beam is simply supported.
Ra + Rb= wL
Ra = Rb =wL / 2
Lets x is measured from left side,then the deflection of beam at any distance x is given as
The maximum deflection of beam will at x = L/2 (mid point )
Answer:
2) 3)
Explanation:
1) Expressing the Division as the summation of the quotient and the remainder
for
118, knowing it is originally a decimal form:
118:2=59 +(0), 59/2 =29 + 1, 29/2=14+1, 14/2=7+0, 7/2=3+1, 3/2=1+1, 1/2=0+1
2)
Similarly, we'll start the process with the absolute value of -49 since we want the positive value of it. Then let's start the successive divisions till zero.
|-49|=49
49:2=24+1, 24:2=12+0,12:2=6+0,6:2=3+0,3:2=1+1,1:2=0+1
100011
3)
The first step on that is dividing by 16, and then dividing their quotient again by 16, so on and adding their remainders. Simply put: