Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
Answer:
I think it would be:
NaCO3 (s)-->Na2O (s) + CO2 (g)
physical change because even though gas formation was observed, the water was undergoing a state change, which means that its original properties are preserved
Explanation:
The boiling of water is a physical change because the original properties of the water is preserved.
- A physical change is the one that alters the physical properties of matter.
- This kind of change is easily reversible as the water can be cooled back.
- No new kinds of matter is produced in this kind of change .
- The molecules of the matter still retains their property after.
During the boiling of water, intermolecular bonds called hydrogen bonds between the water molecules are broken. This makes the individual molecules free.
Learn more:
Hydrogen bonds brainly.com/question/10602513
#learnwithBrainly
Answer:
i think this is the answer
Explanation:
C).50 ML
D)8.5 ph
E)weak acid,strong base,basic
Answer:The volume increases by 11%
Explanation:
When the pressure is decreased, the volume must definitely increase, to maintain the same pressure, the temperature must then also be increased as we see in the question. The volume was increased just as the pressure decreased and the temperature had to be increased to maintain a constant pressure. We have applied the general gas equation in solving the problem.
