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Fynjy0 [20]
3 years ago
6

One city is located north of the equator and experiences average rainfall and warm temperatures. Another city is located exactly

the same distance from the equator, but south. How will these two climate areas be the same or different?
A. The temperature and precipitation will both differ.
B.The temperature and precipitation will be similar.
C.The temperature will differ but the precipitation will be the same.
D. The precipitation will differ but the temperature will be the same.
Chemistry
1 answer:
antoniya [11.8K]3 years ago
3 0
B I think ..........................
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What is competitive exclusion?<br> This is for a lesson about Niche
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the inevitable elimination from a habitat of one of two different species with identical needs for resources.

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1) A 10g sample of H2(g) reacts with a 22g sample of O2(g) according to
solmaris [256]

Answer:

H₂ is excess reactant and O₂ the limiting reactant

Explanation:

Based on the chemical reaction:

2H₂(g) + O₂(g) → 2H₂O

<em>2 moles of H₂ react per mole of O₂</em>

<em />

To find limiting reactant we need to convert the mass of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

10g H₂ * (1mol / 2.016g) = 4.96 moles

<em>Moles O₂ -Molar mass: 32g/mol-:</em>

22g O₂ * (1mol / 32g) = 0.69 moles

For a complete reaction of 0.69 moles of O₂ are needed:

0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂

As there are 4.96 moles,

<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
7 0
3 years ago
The time required for one-half of the atoms from a sample of a radioactive substance to decay is called its _____.
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6 0
3 years ago
If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O
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Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of C_4H_{10} = 1.332 mol

Mass of O_2 = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:  

C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the balanced reaction we conclude that

As, 13 mole of O_2 react with 1 mole of C_4H_{10}

So, 6.504  moles of O_2 react with \frac{6.504}{13}=0.5003 moles of C_4H_{10}

From this we conclude that, C_4H_{10} is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

5 0
3 years ago
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