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OLEGan [10]
3 years ago
8

WILL AWARD BRAINLLIEST!!!!

Physics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

8 feet per second

Explanation:

40 divide by 5=8

Hope this helps :D

zheka24 [161]3 years ago
5 0

<u>Answer:</u> The speed of the dog is 8 ft/s

<u>Explanation:</u>

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

\text{Speed of the dog}=\frac{\text{Distance traveled}}{\text{Time taken}}

We are given:

Distance traveled by dog = 40 ft

Time taken = 5 seconds

Putting values in above equation, we get:

\text{Speed of the dog}=\frac{40ft}{5s}\\\\\text{Speed of the dog}=8ft/s

Hence, the speed of the dog is 8 ft/s

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Explain what an exoskeleton is and what it is made of.
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4 years ago
What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.
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<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.

This Law is originally expressed as follows:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=6.39(10)^{23}kg is the mass of Mars

a=3.4(10)^{6}m  is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2)

T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}    (3)

T=\sqrt{11581157.44 s^{2}}    (4)

Finally:

T=3403.1099s=56.718min    This is the orbital period of a spacecraft in a low orbit near the surface of mars

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