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3 years ago

WILL AWARD BRAINLLIEST!!!!

Physics

2 answers:

Wittaler [7]3 years ago

8 0

Answer:

8 feet per second

Explanation:

40 divide by 5=8

Hope this helps :D

zheka24 [161]3 years ago

5 0

Answer: The speed of the dog is 8 ft/s

Explanation:

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

$\text{Speed of the dog}=\frac{\text{Distance traveled}}{\text{Time taken}}$

We are given:

Distance traveled by dog = 40 ft

Time taken = 5 seconds

Putting values in above equation, we get:

$\text{Speed of the dog}=\frac{40ft}{5s}\\\\\text{Speed of the dog}=8ft/s$

Hence, the speed of the dog is 8 ft/s

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How can I act more like Runa from Kakegurui?

igomit [66]

Answer:

LOVE HER, and just study her, and sometimes just pause and try and act like that, or watch the backstory and go through everything they went through.

Explanation:

Hope this helps

4 0

3 years ago

Read 2 more answers

Consider this situation: A bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, iden

Sergio039 [100]

I know that E.) Tension Force is one of them and B.) Gravity Force but I'm not sure about the others.

5 0

4 years ago

A ball rolls off a desk at a speed of 2 m/s and lands 0.50 seconds later.

Hoochie [10]

Answer:

(a) The ball lands 1 m ahead of the desk's base.

(b) The height of the desk is 1.225 m.

Explanation:

Given:

Initial velocity of the ball is, $u_{0}=2\ m/s$

Time of flight of the ball is, $t=0.50\ s$

(a)

Let the ball fall at a distance of $x$ from the base of the desk and let the height of the desk be $y$ .

The given motion of the ball is a projectile motion that can be divided into 2 mutually perpendicular directions.

Now, considering only the horizontal motion of the ball. The ball not under the influence of any force in the horizontal direction.

Therefore, the distance covered by the ball horizontally is given as:

$x=v_0\times t\\x=2\times 0.50=1\ m$

So, the ball lands 1 m ahead of the desk's base.

(b)

Now, consider only the vertical motion of the ball. The ball is under the influence of gravity.

So, vertical distance can be obtained using Newton's equations of motion.

We use the following equation of motion:

$y-y_0=u_{oy}t+\frac{1}{2}gt^2$

Where,

$y_{0}\rightarrow \textrm{initial vertical position of ball}\\u_{oy}\rightarrow \textrm{initial vertical velocity}\\g\rightarrow \textrm{acceleration due to gravity}\\y\rightarrow \textrm{final position of ball vertically}$

Here, as the ball leaves the desk horizontally, initial velocity is only in the horizontal direction and doesn't have any component in the vertical direction. So, $u_{oy}=0\ m/s$

Plug in $y_0=h,y=0,g=-9.8,u_{oy}=0,t=0.5$ . Solve for $h$ .

$0-h=0+\frac{1}{2}(-9.8)(0.5)^2\\-h=-4.9\times 0.25\\h=1.225\ m$

Therefore, the height of the desk is 1.225 m.

6 0

3 years ago

A given individual is unable to see objects clearly when he is beyond 60 cm. What power lens should be used to correct this prob

Sveta_85 [38]

Answer:

correct option is E

power lens is - 1.667 D

Explanation:

Given data

infinity = 60 cm

to find out

power lens

solution

we know here infinity v = -60 cm because object at infinity

and we take u = - infinity

so we know that

1/f = 1/v - 1/u

1/f = 1 / -60 - 1 / -infinity

1/f = - 1/60

f = - 60 cm = 0.60 m

and we know power of lens = 1/f

so here

power = 1 / -0.60

power = - 1.667 D

so correct option is E

power lens is - 1.667 D

6 0

4 years ago

A parallel-plate capacitor in air has a plate separation of 1.25 cm and a plate area of 25.0 cm2. The plates are charged to a po

Archy [21]

Answer:

(a) Since net charge remains same,after immersion Q is same

(b) I. 14.56pF ii. 3.05V

Explanation:

C = kεA/d

k=1 for air

ε is 8.85x10-12F/m

A = .0025m2

d = .125m

C = 8.85x10-12x.0025/.125 = 1.77x10-13F = 0.177pF

Q = CV = .177pF * 244V = 43.188pC

Since net charge remains same,after immersion Q is same

C = kεA/d, for distilled water k is approx. 80

Cwater = Cair x k

=0.177pF x 80 = 14.16pF

Q is same and C is changed V=Q/c holds. where Q is still 43.188pC and C is now 14.16pF, so V = 43.188pC/14.16pF = 3.05V

c) Change in energy: ΔU = Uwater - Uair

Uwater = Q2/2C = (43.188)2/2x.177pF = 5.27nJ

Uair = Q2/2C = (43.188)2/2x14.16pF = 0.066nJ

ΔU = 5.204nJ

6 0

3 years ago