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3 years ago

WILL AWARD BRAINLLIEST!!!!

Physics

2 answers:

Wittaler [7]3 years ago

8 0

Answer:

8 feet per second

Explanation:

40 divide by 5=8

Hope this helps :D

zheka24 [161]3 years ago

5 0

<u>Answer:</u> The speed of the dog is 8 ft/s

<u>Explanation:</u>

Speed is defined as the ratio of distance traveled to the time taken.

To calculate the distance traveled by boat, we use the equation:

$\text{Speed of the dog}=\frac{\text{Distance traveled}}{\text{Time taken}}$

We are given:

Distance traveled by dog = 40 ft

Time taken = 5 seconds

Putting values in above equation, we get:

$\text{Speed of the dog}=\frac{40ft}{5s}\\\\\text{Speed of the dog}=8ft/s$

Hence, the speed of the dog is 8 ft/s

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Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S

Vlada [557]

Answer:

The required angular speed the neutron star is 10992.32 rad/s

Explanation:

Given the data in the question;

mass of the sun M $_S$ = 1.99 × 10³⁰ kg

Mass of the neutron star

M $_N$ = 2( M $_S$ )

M $_N$ = 2( 1.99 × 10³⁰ kg )

M $_N$ = ( 3.98 × 10³⁰ kg )

Radius of neutron star R $_N$ = 13.0 km = 13 × 10³ m

Now, let mass of a small object on the neutron star be m

angular speed be ω $_N$ .

During rotational motion, the gravitational force on the object supplies the necessary centripetal force.

GmM $_N$ = / R $_N$ ² = mR $_N$ ω $_N$ ²

ω $_N$ ² = GM $_N$ = / R $_N$ ³

ω $_N$ = √(GM $_N$ = / R $_N$ ³)

we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²

we substitute

ω $_N$ = √( ( 6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)

ω $_N$ = √( 2.65466 × 10²⁰ / 2.197 × 10¹²

ω $_N$ = √ 120831133.3636777

ω $_N$ = 10992.32 rad/s

Therefore, The required angular speed the neutron star is 10992.32 rad/s

5 0

3 years ago

If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?

Drupady [299]

Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

5 0

3 years ago

Read 2 more answers

A 0.2 kg baseball is pitched with a velocity of 40 m/s and is then batted to the pitcher with a velocity of 60 m/s. What is the

sergey [27]

Answer:

The magnitude of change in the ball's momentum is 4 kgm/s

Explanation:

Given;

mass of the ball, m = 0.2 kg

initial velocity of the ball, u = 40 m/s

final velocity experienced by the ball, v = 60 m/s

Therefore, the change in momentum of the ball is given as final momentum minus initial mometum;

ΔP = mv - mu

ΔP = m(v-u)

ΔP = 0.2 (60 - 40)

ΔP = 4 kgm/s

Therefore, the magnitude of change in the ball's momentum is 4 kgm/s

3 0

3 years ago

onsider what happens when you jump up in the air. Which of the following is the most accurate statement?A) Since the ground is s

Likurg_2 [28]

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

5 0

4 years ago

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago