The quantity doesn't matter when it comes to boiling point, it's an Intensive property. The boiling point will not change. = 56°C
Answer:
Transitional metals are good conductors of both heat and electricity.
But since there aren't any. It could be Calcium.
No because they have the same number of protons not neutrons. fine, their mass nos are equal but isotopy is due to different number of neutrons.
Answer:
Option B
Explanation:
Magnesium is an alkali earth metal and chlorine is a nonmetal. Due to this, and their differences in electronegativity, the elements form an ionic bond. Since magnesium has two valence electrons, it will give them up to two chlorine atoms (which has 7 valence electrons), which needs them to complete its octet. From this, magnesium forms a cation, and will have the ion formula Mg(2+). The two chlorine atoms form anions, and will have the ion formula Cl(1-).
Terms:
- Cation: a positively charged ion
- Anion: a negatively charge ion.
- Electronegativity: the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.
Answer:- 14.9 M
Solution:- Given commercial sample of ammonia is 28% by mass. Let's say we have 100 grams of the sample. Then mass of ammonia would be 28 grams.
Density of the solution is given as 0.90 grams per mL.
From the mass and density we could calculate the volume of the solution as:

= 111 mL
Let's convert the volume from mL to L as molarity is moles of solute per liter of solution.
= 0.111 L
Now, we convert grams of ammonia to moles on dividing the grams by molar mass. Molar mass of ammonia is 17 gram per mole.

= 1.65 mole
To calculate the molarity we divide the moles of ammonia by the liters of solution:

= 14.9 M
So, the molarity of the given commercial sample of ammonia is 14.9 M.