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4 years ago

11

Why are gamma rays not affected by a magnet as they Passover it

2 answers:

avanturin [10]4 years ago

7 0

Gamma rays are not magnetic

BartSMP [9]4 years ago

7 0

It is because they have no charge and they are waves. So, it basically means that magnet affect only charged substances, neutral substances like gamma rays, x-rays are not affected.
Hope this helps!

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Problem PageQuestion Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature

Marrrta [24]

Complete question

The complete question is shown on the first uploaded image

Answer:

The value is $K_c = 2.69 *10^{-5}$

Explanation:

From the question we are told that

The equation is

$Fe_20_3_{(s)}+3H_{(g)}\to2Fe_{(s)}+3H_2O_{(g)}$

Generally the equilibrium is mathematically represented as

$K_c = \frac{[H_2O]^2}{[H_2]^3}$

Here $[H_2O]$ is the concentration of water vapor which is mathematically represented as

$[H_2O ] = \frac{n_w}{V_s }$

Here $V_s$ is the volume of the solution given as 8.9 L

$n_w$ is the number of moles of water vapor which is mathematically represented as

$n_w = \frac{m_w}{Z_w}$

Here $m_w$ is the mass of water given as 2.00 g

and $Z_w$ is the molar mass of water with value 18 g/mol

So

$n_w = \frac{2}{18}$

=> $n_w = 0.11 \ mol$

So

$[H_2O ] = \frac{0.11}{8.9 }$

=> $[H_2O ] = 0.01236 \ M$

Also

$[H]$ is the concentration of hydrogen gas which is mathematically represented as

$[H ] = \frac{n_v}{V_s }$

Here $V_s$ is the volume of the solution given as 8.9 L

$n_v$ is the number of moles of hydrogen gas which is mathematically represented as

$n_v = \frac{m_v}{Z_v}$

Here $m_w$ is the mass of water given as 4.77 g

and $Z_v$ is the molar mass of water with value 2 g/mol

So

$n_w = \frac{4.77}{2}$

=> $n_w = 2.385 \ mol$

So

$[H_2O ] = \frac{2.385}{8.9 }$

=> $[H_2O ] = 0.265 \ M$

So

$K_c = \frac{( 0.01236 )^3}{ (0.265 )^2}$

=> $K_c = 2.69 *10^{-5}$

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Answer:

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