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3 years ago

Solute and solvent of C12H22O11

Chemistry

1 answer:

nasty-shy [4]3 years ago

8 0

Answer:

sugar is the solute and water is the solvent

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Find any errors in the orbital notation diagrams below and correct them.

riadik2000 [5.3K]

Answer:

See explanation.

Explanation:

A. 2s is incorrect, the right arrow should be pointing downwards.

B. In 2p, the last box has 3 arrows. This is invalid. Each box can only store 2 arrows(electrons). The last arrow should be moved to a 3p orbital (new box).

C. In this one, the arrows switched directions (left is down and right is up). You could fix each box or just the last one (in 3p) to point downwards.

4 0

2 years ago

Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 3.31 × 10−13 at some temperature, compute

Artyom0805 [142]

Since Kw= [H⁺][OH⁻], and the concentration of both substances are the same, the equation is now Kw=[H⁺]²
So,
3.31x10⁻¹³ = [H⁺]²
Take the square root= 5.75x10⁻⁷
Then take the negative log to find the pH:
-log(5.75x10⁻⁷) = 6.25

5 0

3 years ago

why is nitrous oxide sedation especially useful for control of soft tissue discomfort during dental hygiene procedure

Stolb23 [73]

Answer:

Because it has a quickly sedative effect and it has antimicrobial effect.

Explanation:

This gas is useful because is used to trait pain, reduce anxiety and promote relaxation, slow down the body reaction, so the dentist can use it to calm down the patients.

If the patient present some injuries, this gas can help in wound healing.

7 0

3 years ago

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)

Paha777 [63]

<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Stoichiometry

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

Step 2: Identify Conversions

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Stoichiometry

Set up: $\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
Multiply/Divide: $\displaystyle 16.6685 \ g \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

16.6685 g H₂O ≈ 16.7 g H₂O

6 0

2 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

malfutka [58]

Answer: I think G.

Explanation:

8 0

3 years ago

Read 2 more answers