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Mama L [17]
3 years ago
12

An object has a force of 10 newtons from the right and 17 newtons from the left. Once the object starts moving toward the right,

an additional force of 7 newtons is applied from the right. What can you conclude about the direction of motion of the object after the application of the additional force? The object will continue moving toward the right. The object will slow, stop, and then begin to move toward the left. The object will come to a halt. The object will accelerate in its motion to the right.
Physics
2 answers:
Debora [2.8K]3 years ago
5 0
The object will come to a halt.

Resultant force at start:17-10=7 to the left
When additional force is added to the right,it balances the forces acting in the object.

7N to the right and 7N to the left suggests that the object will come to a halt as it is in equilibrium.
GarryVolchara [31]3 years ago
3 0

Answer:

The object will continue moving toward the right, but its rate of acceleration will decrease.

Explanation:

Since the second force is operating in the opposite direction as the first force, the forces work against each other. However, since the second force has a smaller magnitude than the first force

7 N < 10 N

the second force is not strong enough to balance or overcome the first force.

Therefore, a net force of 3 N will be acting on the object, which will cause it to accelerate toward the right, but it will accelerate at a slower rate than before.

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Triss [41]

Answer:

Hey

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6 0
3 years ago
How can we find the volume of a small pebble with the help of measuring cyilinder
ad-work [718]

We can find the volume of a small pebble with the help of measuring cylinder by using the water displacement method. <span>The </span>water displacement method<span> <span>is the process of measuring the volume of an irregularly shaped object by immersing it in water. </span></span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0
3 years ago
A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?
Len [333]

Answer:

Given that

V2/V1= 0.25

And we know that in adiabatic process

TV^န-1= constant

So

T1/T2=( V1 /V2)^ န-1

So = ( 1/0.25)^ 0.66= 2.5

Also PV^န= constant

So P1/P2= (V2/V1)^န

= (1/0.25)^1.66 = 9.98

A. RMS speed is

Vrms= √ 3RT/M

But this is also

Vrms 2/Vrms1= (√T2/T1)

Vrms2=√2.5= 1.6vrms1

B.

Lambda=V/4π√2πr²N

So

Lambda 2/lambda 1= V2/V1 = 0.25

So the mean free path can be inferred to be 0.25 times the first mean free path

C. Using

Eth= 3/2KT

So Eth2/Eth1= T2/T1

So

Eth2= 2.5Eth1

D.

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Cvf= Cvi

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5 0
3 years ago
Read 2 more answers
What must the diver's minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, wh
Dafna1 [17]

Answer:

1.08 m/s

Explanation:

This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.

Time taken to fall 9.5 m

vertical acceleration = a = 9.8 m/s^2.

vertical velocity = 0, (since there is only horizontal component for velocity, )

distance traveled  s = 9.5 m.

Substituting these values in the equation

s= u \timest+0.5at^{2}

t= \sqrt{\frac{2s}{g} }

t=\sqrt{\frac{2\times9.5}{9.8} }

⇒ t= 1.392 sec

Velocity needed

We know the time taken (1.392 s) to travel 1.5 m,

So velocity = 1.5 m / 1.392 s = 1.08 m/s

hence velocity of the diver must be at least 1.08 m/s

4 0
3 years ago
5 points
olga2289 [7]

Answer:

d. 5 ohms

Explanation:

For resistors in parallel, the equivalent resistance is found with:

1/Req = ∑(1/R)

1/R = 1/15 + 1/15 + 1/15

1/R = 3/15

R = 15/3

R = 5

8 0
3 years ago
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