Answer:
- a) 2N₂O(g) → 2N₂(g) + O₂(g)
Explanation:
Arrange the equations in the proper way for better understanding.
T<em>he reaction between nitrogen and oxygen is given below:</em>
<em />
- <em>2N₂(g) + O₂(g) → 2N₂O(g)</em>
<em />
<em>We therefore know that which of the following reactions can also occur?</em>
<em />
- <em>a) 2N₂O(g) → 2N₂(g) + O₂(g)</em>
- <em>b) N₂(g) + 2O₂(g) → 2NO₂(g)</em>
- <em>c) 2NO₂(g) → N₂(g) + 2O₂(g)</em>
- <em>d) None of the Above</em>
<h2>Solution</h2>
Notice that the first equation, a) 2N₂O(g) → 2N₂(g) + O₂(g), is the reverse of the original equation, 2N₂(g) + O₂(g) → 2N₂O(g).
The reactions in gaseous phase are reversible reactions that can be driven to one or other direction by modifying the conditions of temperature or pressure.
Thus, the equilibrium equation would be:
Which shows that both the forward and the reverse reactions occur.
Whether one or the other are favored would depend on the temperature and pressure: high temperatures would favor the reaction that consumes more heat (the endothermic reaction) and high pressures would favor the reaction that consumes more moles.
Thus, by knowing that one of the reactions can occur you can conclude that the reverse reaction can also occur.
The following chemical reaction will occur:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
Explanation:
Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.
The chemical reaction is:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
where:
(l) - liquid
(s) - solid
Learn more about:
balancing chemical equations
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Independent variables don't change
Dependent variables change as a result of the alteration made during the experiment
Explanation:
As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.
As, molar mass of ethanol = 46.07 g/mol
Therefore, no. of moles of ethanol will be calculated as follows.
No. of moles = 
=
=
mol
As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.
Molarity = 
= 
=
mol/L
Since, for the given solution Molarity = osmolarity
Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol in 1 L is
osmol/L.
It has only single bonds.So it is saturated