Here, we may apply the equation of state for an ideal gas, which is:
PV = nRT
We may substitute the number of moles, n, with:
moles = mass / molecular mass
PV = mRT/Mr
Mr = (mRT)/PV
Substituting the values:
Mr = (81.5 * 0.082 * 307) / (1.75 * 4.92)
Mr = 238.3
The molar mass of the gas is 238.3 grams per mole.
A pendulum. Hold it high and it has potential energy but no kinetic energy because it is still. As it moves down when you drop it, it changes to kinetic energy and moves faster and faster until it's at the bottom where it has no potential energy. However, it still has momentum, so now it is changed to potential energy as it moves up the other side
Answer:
True
Explanation:
This is because, The hydroboration oxidation of an alkene which is isobutene in the presence of a catalyst will result to alcohol as the product . Therefore, the OH group will attach or link itself to the carbon which is less obstructed. Thus this reaction is in accordance to Anti-Markownikoff's rule.
So isobutene on hydroboration oxidation will produce ter isobutyl alcohol.
