Answer:
The question is incomplete, below is the complete question "A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is F with arrow = Fxi hat + (7.00 N)j − (5.00 N)k and the corresponding torque about the origin is vector tau = (4 N · m)i hat + (10 N · m)j + (11N · m)k.
Determine Fx."
Explanation:
We asked to determine the "x" component of the applied force. To do this, we need to write out the expression for the torque in the in vector representation.
torque=cross product of force and position . mathematically this can be express as
Where
and the position vector
using the determinant method to expand the cross product in order to determine the torque we have
![\left[\begin{array}{ccc}i&j&k\\2&-3&2\\ F_{x} &7&-5\end{array}\right]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C2%26-3%262%5C%5C%20F_%7Bx%7D%20%267%26-5%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C)
by expanding we arrive at
since we have determine the vector value of the toque, we now compare with the torque value given in the question
if we directly compare the j coordinate we have
<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
Answer:
According to Kepler's 3rd law.
It states that the orbital period, T is related to the distance, r as:
T²
= 4
π²r³
/G M
where G is the universal gravitational constant = 6.673 × 10⁻¹¹ Nm²/kg²
Rearranging for M should give Jupiter's mass.
M =
4
π²r³/GT²
T= 1.77 days × 24 h/day × 60 min/h × 60 s/min = 1.53 × 10⁵ s
r = 4.22x10⁸ m
M = 4π² ((4.22 × 10⁸ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (1.53 × 10⁵ s)²)
M = 1.90 × 10²⁷kg
The mass of Jupiter is 1.90 × 10²⁷kg.
1.90 × 10²⁷kg
T= 7.16 days × 24 h/day × 60 min/h × 60 s/min = 6.19 × 10⁵s
r = 1.07x10⁹ m
M = 4π² ((1.07 × 10⁹ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (6.19 × 10⁵ s)²)
M = 1.90 × 10¹⁷kg
The mass of Jupiter is 1.90 × 10¹⁷kg.
THE RESULTS TO PART A and B ARE NOT CONSISTENT. The reason is because of the difference in radius of each satellites from Jupiter. i.e the farther away the moons, the smaller they become in space and the more the number of days to complete an orbit.
helium group no val elect
mg is reactive when activated. when burned, very intense
pot\asssium 1 valence elect ... KCl eg
theone with H and sodium in it
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D.) Vertical relationships involve unequal status, while horizontal relationships represent equal status.
HOPE THIS HELPS!
