The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
compression forces can cause mountains to form or earthquakes to occur depending on how the earth's crust reacts to the force
Answer:
Explanation:
They substituted the value of M₁.
∑F = ma
M₁ a = T₁ - F
M₁ a = T₁ - Nμ
M₁ a = T₁ - M₁g μ
Given that M₁ = 2, g = 9.81, and μ = 0.25:
(2) a = T₁ - (2) (9.81) (0.25)
Answer:
a) 37.70 m/s
b)710.6 m/s²
Explanation:
Given that ;
Mass of object = 2 kg
Radius of the motion = 2m
Frequency of motion = 3 rev/s
The formula to apply is;
v= 2πrf where v is linear speed
v = 2×π×2×3 =12π = 37.70 m/s
Centripetal acceleration is given as;
a= 4×π²×r×f²
a= 4×π²×2×3²
a=710.6 m/s²