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vichka [17]
3 years ago
12

Which of the following changes requires an oxidizing agent?

Chemistry
2 answers:
KatRina [158]3 years ago
8 0
2F⁻ → F₂ + 2e⁻

(mainly electrochemical oxidation)
Ad libitum [116K]3 years ago
4 0

Answer : The correct option is, 2F^-\rightarrow F_2+2e^-

Explanation :

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Oxidizing agent : It is defined as the substance which has ability to oxidize the other substances by gaining electrons.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the substance which has ability to reduce the other substances by losing electrons.

From the given options, we conclude that

(1) O_2+4e^-\rightarrow 2O^{2-}

(2) SO_3+H_2O\rightarrow SO_4^{2-}+2H^+

(3) MnO_2+4H^++2e^-\rightarrow Mn^{2+}+2H_2O

The reaction 1, 2 and 3 shows the reduction reaction. So, it requires a reducing agent.

(4) 2F^-\rightarrow F_2+2e^-

The reaction 4 shows the oxidation reaction. Therefore, it requires an oxidizing agent.

Therefore, the correct option is, 2F^-\rightarrow F_2+2e^-

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During an investigation, a student burns magnesium to form magnesium oxide. The starting mass of magnesium is measured as 21.3 g
enot [183]

Answer:

Percentage yield = 85.2%

Explanation:

Given data:

Mass of Mg = 21.3 g

Actual yield of MgO = 30.2 g

Percentage yield = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

Number of moles of Mg = mass/molar mass

Number of moles of Mg = 21.3 g / 24.3 g/mol

Number of moles of Mg = 0.88 mol

Now we will compare the moles of MgO with Mg.

                 Mg           :               MgO

                 2               :               2

                0.88             :             0.88

Mass of MgO:           

Mass of MgO= moles × molar mass

Mass of MgO= 0.88 mol × 40.3g/mol

Mass of MgO =  35.46 g

Actual yield of MgO = 30.2 g

Percentage yield:

Percentage yield = Actual yield/theoretical yield × 100

Percentage yield = 30.2 g/ 35.46 g × 100

Percentage yield = 85.2%

3 0
3 years ago
Which of the following best describes the relationship of solar UV radiation to the environment?
aliya0001 [1]
<span> UV radiation are high energy radiations and they are mutation causing agents so
</span>Mutagen <span> best describes the relationship of solar UV radiation to the environment
so option A is correct
hope it helps</span>
4 0
3 years ago
Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a h
makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: SiO_{2}+3C\rightarrow SiC+2CO

Molar mass of SiC = 40.11 g/mol

Molar mass of SiO_{2} = 60.08 g/mol

So, 100.0 kg of SiO_{2} = \frac{100.0\times 10^{3}}{60.08} moles of SiO_{2} = 1664 moles of SiO_{2}

According to balanced equation, 1 mol of SiO_{2} produces 1 mol of SiC

Therefore, 1664 moles of SiO_{2} produce 1664 moles of SiC

Mass of 1664 moles of SiC = (1664\times 40.11)g = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]\times 100%

                                 = \frac{51.4kg}{66.74kg}\times 100 %

                                 = 77.0%

4 0
3 years ago
Please help ————//-//
grandymaker [24]
Probably b because soil can’t be the exact same and so that cancels out a and d
6 0
3 years ago
Read 2 more answers
21,980 mg of phosphorus reacts in a gas jar containing oxygen. The resulting oxide weighed 50.000 g. The percent composition of
stealth61 [152]

Answer: False

Explanation:

8 0
3 years ago
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