Answer:
![M=235.42g/mol](https://tex.z-dn.net/?f=M%3D235.42g%2Fmol)
Explanation:
Hello!
In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:
![2n_{acid}=n_{base}](https://tex.z-dn.net/?f=2n_%7Bacid%7D%3Dn_%7Bbase%7D)
It means that the moles of acid can be computed given the volume and concentration of NaOH:
![n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol](https://tex.z-dn.net/?f=n_%7Bacid%7D%3D%5Cfrac%7BM_%7Bbase%7DV_%7Bbase%7D%7D%7B2%7D%20%3D%5Cfrac%7B0.044391L%2A0.111mol%2FL%7D%7B2%7D%20%5C%5C%5C%5Cn_%7Bacid%7D%3D2.46x10%5E%7B-4%7Dmol)
It means that the approximate molar mass of the acid is:
![M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bm_%7Bacid%7D%7D%7Bn_%7Bacid%7D%7D%20%5C%5C%5C%5CM%3D%5Cfrac%7Bm_%7Bacid%7D%7D%7Bn_%7Bacid%7D%7D%20%3D%5Cfrac%7B0.58g%7D%7B2.46x10%5E%7B-3%7Dmol%7D%5C%5C%5C%5CM%3D235.42g%2Fmol)
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Answer:
Water moves through the help of living organisms in an ecosystem. ... Plants absorbs water through their root system and loss by transpiration. Water also moves through the living organisms in an ecosystem. Other nonliving processes such as evaporation, precipitation, water returns back into the atmosphere.
Explanation: welcome
2.50 x 2/1 = 5 mol of Citric Acid
5 x (3+72+5+112) = 960g of Citric Acid
Answer: 960g of Citric Acid
Answer:the ability to be dissolved, especially in water.
Explanation:
On the lab the text is kind of too far zoomed out so u can’t really read it it’s like blurry