Answer:
Ka = 1.39x10⁻⁶
Explanation:
A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
<em>Where Ka is:</em>
Ka = [H⁺] [X⁻] / [HX]
<em>Where [] is the molar concentration in equilibrium of each specie.
</em>
The equilibrium is reached when some HX reacts producing H+ and X-, that is:
[HX] = 1.64M - X
[H⁺] = X
[X⁻] = X
As pH is 2.82 = -log [H⁺]:
[H⁺] = 1.51x10⁻³M:
[HX] = 1.64M - 1.51x10⁻³M = 1.638M
[H⁺] = 1.51x10⁻³M
[X⁻] = 1.51x10⁻³M
And Ka is:
Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]
<h3>Ka = 1.39x10⁻⁶</h3>
Answer:
MgBr(aq) + (NH4)3PO4(aq) -------> NH4Br(aq) + Mg3(PO4)2(s)
Explanation:
Answer:
The biological significance is that it is the normal human body temperature and also the optimum temperature of the enzyme.
Explanation:
- Enzymes are biological catalysts that speed up the rate of chemical reactions.
- Enzymes catalyze specific reactions by working on a specific substrate to convert it into a product.
- The rate of enzyme activity depends on several factors which include pH, temperature, substrate concentration, and enzyme concentration among others.
- Enzymes work best at a specific pH and temperature known as optimum pH and optimum temperature respectively.
- In this case, enzyme amylase works best at a temperature of 37° C which is equivalent to the normal human body temperature.
All of the lower case letters are recessive
Answer:
molar mass (molar weight)
Explanation:
