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lesantik [10]
3 years ago
8

What is normal for a spring that obeys hook's law ?

Physics
2 answers:
Bezzdna [24]3 years ago
7 0
A spring that obeys Hooke's law has a spring force constant of 272 N/m. This spring is then stretched by 28.6 cm
ArbitrLikvidat [17]3 years ago
6 0
How are we supposed to know
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Grace [21]

Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque  = distance from pivot *  perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

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3 years ago
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69\times 7 = 483 kg\cdot m/s
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ivann1987 [24]

Answer:

13.33 or 13 1/3m/s (meters per second)

Explanation:

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