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Margarita [4]
3 years ago
9

Why is it better to use the metric system, rather than the English system, in scientific measurement?

Physics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

A

Explanation:

fiasKO [112]3 years ago
4 0

A. The English system uses one unit for each category of measurement.

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To help fight off disease and viruses
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A cell of e.M.F 1.5v and internal resistance 2.5ohm is connected in series with an ammeter of resistance 0.5ohm. Calculate the c
Tju [1.3M]

Given :

A cell of e.m.f  1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A

Therefore, the current in the circuit is 0.5 A.

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3 years ago
What is the relationship between electric and magnetic fields?
geniusboy [140]
Moving point charges, such as electrons, produce complicated but well known magnetic fields that depend on the charge, velocity, and acceleration of the particles. Magnetic field lines form in concentric circles around a cylindrical current-carrying conductor, such as a length of
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3 years ago
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A bar B made of some material is attracted by a magnet. Is the bar B magnetised ?​
Dvinal [7]

Answer:

No, it is not magnetized.

Explanation:

Bar B does not necessarily have to be magnetized before it can be attracted to a magnet. It just has to be a magnetic material such as Iron.

If bar B were magnetized, it could either be attracted or repelled by the magnet since this would depend on the side of the pole of bar B facing it.

Since we are not given any information about bar B other than it is attracted to the magnet, it is thus not magnetized.

7 0
3 years ago
An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-
kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle(m_1)=3\times 10^{-28} kg

mass of heavier Particle(m_2)=1.51\times 10^{-27} kg

speed of lighter particle(v_1)=0.834 c

Let speed of heavier particle=v_2

and Momentum of the particle is given by

P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}

P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}

P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}

P_1=8.219\times 10^{-28} kg c

P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}

as momentum is conserved therefore P_1=P_2

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3 years ago
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