Answer:
t = 3 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 15 [m/s]
g = gravity acceleration = 10 [m/s²]
t = time [s]
Now replacing we have:
![0 = 15 -10*t\\10*t=15\\t= 1.5[s]](https://tex.z-dn.net/?f=0%20%3D%2015%20-10%2At%5C%5C10%2At%3D15%5C%5Ct%3D%201.5%5Bs%5D)
Note: In the equation above the gravity acceleration is negative, because the movement of the ball bearing is pointing againts the gravity acceleration.
The time calculated is only when the ball bearing reaches the highest elevation, and it will take the same time for descending, therefore the total time is:
t = 1.5 + 1.5 = 3 [s]
Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.
An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.
In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.
It is a kinetic type of jump
Answer:
generate electricity or power
Answer:
evaporation to condensation to precipitation.