The box is in equilibrium, so Newton's second law says
<em>n</em> + (-<em>w</em>) = 0
65 N + (-<em>f</em> ) = 0
where <em>n</em> denotes the magnitude of the normal force, <em>w</em> denotes the weight of the box, and <em>f</em> denotes the magnitude of the friction force.
The box has a weight of
<em>w</em> = (25 kg) (9.80 m/s²) = 245 N
so <em>n</em> = 245 N, too.
The friction force has magnitude
<em>f</em> = 65 N
and is proportional to the normal force by a factor of <em>µ</em>, the coefficient of kinetic friction. So we have
65 N = <em>µ</em> (245 N) → <em>µ</em> ≈ 0.26
Answer:
Both nuclear fusion and fission reactions
Both fission and fusion are nuclear reactions that produce energy, but the applications are not the same. Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.
Hoped that helped :)
Explanation:
Answer:
The centripetal acceleration is 30 m/s²
Explanation:
Given that,
Radius = 0.30 m
Acceleration = 2.0 rad/s²
Time = 5.0
We need to calculate the centripetal acceleration
Using formula of angular velocity

Where,
a = acceleration
t = time
Put the value into the formula


Using formula of centripetal acceleration



Hence, The centripetal acceleration is 30 m/s²
Answer:
The right answer is 8.9 x 10^-3 M/min
Explanation:
A → B
-d [A]/dt = K [A]
ΔA/Δt = - (C2 -C1)/t2 - t1
= - (0.11 - 0.91)/90
= 8.9 x 10^-3 M/min
Answer:
(a)20.65g
(b)0.19m
Explanation:
(a) The total mass would be it's mass per length multiplied by the total lenght
0.355(50 + 23*0.355) = 20.65 g
(b) The center of mass would be at point c where the mass on the left and on the right of c is the same
Hence the mass on the left side would be half of its total mass which is 20.65/2 = 10.32 g


