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Montano1993 [528]
3 years ago
5

- What is the total distance traveled by the car

Physics
1 answer:
slega [8]3 years ago
7 0

*Graph is attached with the answer*

Answer:

Total distance traveled by the car is 40 m

Explanation:

It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity

So, we solved this question in 2 parts

Part 1:

               initial velocity = v₁ = 0 m/s

               final velocity = v₂ = 10 m/s

                time = t = 4 s

                acceleration = a = (v₂ - v₁)/t

                                a = 10/4 = 2.5 m/s²

Using 3rd equation of motion

                2as = v₂² - v₁²

                 2(2.5)s = 10²

                      s₁ = 100/5

                     s₁ = 20 m

Part 2:

            s₂ = v₂t

            s₂ = 10 × 2

            s₂ = 20 m

Total distance = S = s₁ + s₂

                              = 20 + 20

                          S = 40 m

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A 25 kg box is being pulled at a constant velocity with a tension force of 65 N. what is the coefficient of friction between the
DiKsa [7]

The box is in equilibrium, so Newton's second law says

<em>n</em> + (-<em>w</em>) = 0

65 N + (-<em>f</em> ) = 0

where <em>n</em> denotes the magnitude of the normal force, <em>w</em> denotes the weight of the box, and <em>f</em> denotes the magnitude of the friction force.

The box has a weight of

<em>w</em> = (25 kg) (9.80 m/s²) = 245 N

so <em>n</em> = 245 N, too.

The friction force has magnitude

<em>f</em> = 65 N

and is proportional to the normal force by a factor of <em>µ</em>, the coefficient of kinetic friction. So we have

65 N = <em>µ</em> (245 N)   →  <em>µ</em> ≈ 0.26

7 0
3 years ago
Both nuclear fusion and nuclear fission reactions____
castortr0y [4]

Answer:

Both nuclear fusion and fission reactions

Both fission and fusion are nuclear reactions that produce energy, but the applications are not the same. Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.

Hoped that helped :)

Explanation:

6 0
3 years ago
Read 2 more answers
A 0.30-m-radius automobile tire accelerates from rest at a constant 2.0 rad/s2. What is the centripetal acceleration of a point
lianna [129]

Answer:

The centripetal acceleration is 30 m/s²

Explanation:

Given that,

Radius = 0.30 m

Acceleration = 2.0 rad/s²

Time = 5.0

We need to calculate the centripetal acceleration

Using formula of angular velocity

\omega=a\times t

Where,

a = acceleration

t = time

Put the value into the formula

\omega=2.0\times5.0

\omega=10\ rad/s

Using formula of centripetal acceleration

a_{c}=r\omega^2

a_{c}=0.30\times10^2

a_{c}=30\ m/s^2

Hence, The centripetal acceleration is 30 m/s²

8 0
3 years ago
For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91
marishachu [46]

Answer:

The right answer is 8.9 x 10^-3 M/min

Explanation:

           A → B

-d [A]/dt  = K [A]

ΔA/Δt     = - (C2 -C1)/t2 - t1

               = - (0.11 - 0.91)/90

               = 8.9 x 10^-3 M/min

7 0
3 years ago
A rod of length 35.50 cm has linear density (mass per length) given by λ = 50.0 + 23.0x where x is the distance from one end, an
hram777 [196]

Answer:

(a)20.65g

(b)0.19m

Explanation:

(a) The total mass would be it's mass per length multiplied by the total lenght

0.355(50 + 23*0.355) = 20.65 g

(b) The center of mass would be at point c where the mass on the left and on the right of c is the same

Hence the mass on the left side would be half of its total mass which is 20.65/2 = 10.32 g

c(50 + 23c) = 10.32

23c^2 + 50c - 10.32 = 0

c \approx 0.19m

7 0
3 years ago
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