- What is the total distance traveled by the car
1 answer:
*Graph is attached with the answer*
Answer:
Total distance traveled by the car is 40 m
Explanation:
It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity
So, we solved this question in 2 parts
Part 1:
initial velocity = v₁ = 0 m/s
final velocity = v₂ = 10 m/s
time = t = 4 s
acceleration = a = (v₂ - v₁)/t
a = 10/4 = 2.5 m/s²
Using 3rd equation of motion
2as = v₂² - v₁²
2(2.5)s = 10²
s₁ = 100/5
s₁ = 20 m
Part 2:
s₂ = v₂t
s₂ = 10 × 2
s₂ = 20 m
Total distance = S = s₁ + s₂
= 20 + 20
S = 40 m
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Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
