*Graph is attached with the answer*
Answer:
Total distance traveled by the car is 40 m
Explanation:
It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity
So, we solved this question in 2 parts
Part 1:
initial velocity = v₁ = 0 m/s
final velocity = v₂ = 10 m/s
time = t = 4 s
acceleration = a = (v₂ - v₁)/t
a = 10/4 = 2.5 m/s²
Using 3rd equation of motion
2as = v₂² - v₁²
2(2.5)s = 10²
s₁ = 100/5
s₁ = 20 m
Part 2:
s₂ = v₂t
s₂ = 10 × 2
s₂ = 20 m
Total distance = S = s₁ + s₂
= 20 + 20
S = 40 m
Answer:
a. The angular frequency is doubled.
e. The period is reduced to one-half of what it was.
Explanation:
Angular frequency is given as;
ω = 2πf
when the frequency is doubled
Thus, the angular frequency will be doubled.
Amplitude in simple harmonic motion is the maximum displacement.
Frequency is related to period in simple harmonic motion as given in the equation below;
when the frequency is doubled;
Thus, the period will be reduced to one-half of what it was.