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solmaris [256]
3 years ago
6

White gold is an alloy that typically contains 60.0% by mass gold and the remainder is platinum. if 175 g of gold are available,

how many grams of platinum are required to combine with the gold to form this alloy? answers
Chemistry
1 answer:
weeeeeb [17]3 years ago
5 0
If a sample of white gold alloy contains 60 percent by mass of gold while the remaining is platinum, then the alloy would contain 40 percent by mass of platinum. <span>Percentage by mass is the amount in mass units of a component in a mixture per 100 unit if mass of the total mixture. We are given the amount of gold available, this represents the 60 percent of the alloy. We calculate for the amount of platinum needed as follows:

Percent of platinum = mass of platinum / mass of gold + mass of platinum
0.40 = mass of platinum / 175 g + mass of platinum
mass of platinum = 117 g</span>
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Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

=  \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}

= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

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