3 years ago

What is the period of the sinusoidal function? [Enter the answer in the box]

Mathematics

1 answer:

Gnoma [55]3 years ago

4 0

I️ swear I️ knew how to do this

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tamaranim1 [39]

Answer:

The answer would be f(x)= 710·4^t

Step-by-step explanation:

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Solve: x²+5x-6 = 0 <br>Answer please

DochEvi [55]

ANSWER: x = 1 or x = -6
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2 years ago

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kaitlin received a $70 gift card for a coffee store. she used it in buying some coffee that cost $7.69 per pound. after buying t

aksik [14]

Kaitlin bought 4 pounds of coffee.

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3 years ago

6/8 ÷ 2/3 pleas help me

butalik [34]

Answer:

$\frac{6}{8} \div \frac{2}{3}$

Simplify,

$\frac{6}{8} = \frac{3}{4}$

So now,

$\frac{3}{4} \div \frac{2}{3} \\ = \frac{3}{4} \times \frac{3}{2} \\ = \frac{3 \times 3}{4 \times 2} \\ = \frac{9}{8} \\ = 1.125$

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3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

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3 years ago